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solmaris [256]
3 years ago
11

What is the slope of the lines! HELP PLEASE!!! 20points

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
3 0

Answer:

1/5

Step-by-step explanation:

pick any points, for example (6, -1) and (11, 0)

slope is m= (y2-y1) / (x2-x1) = -1-0 / 6-11 = -1 / -5 = 1/5

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Devya sold shirts to raise money for a school trip. The amount of money she received from her sales is proportional to the numbe
azamat
It might be C. I used the process of elimination, so I'm not so certain
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Which of the following is equal to the expression below? (160x243)^1/5
Kipish [7]
160 = 2 x 2 x 2 x 2 x 2 x 5 = 2^5 x 5
243 = 3 x 3 x 3 x 3 x 3 = 3^5
So
(160 * 243)^1/5
= 5th root of (160 * 243)
= 5th root of (2^5 * 5 * 3^5)
= 2 * 3 * (5th root of 5)
= 6 * (5th root of  5)
Answer is D. 6 * (5th root of  5)
3 0
3 years ago
True or false: the equation tan^2x+1=sec^2x
zhenek [66]

ANSWER

True

EXPLANATION

The given trigonometric equation is:

{ \tan}^{2} x + 1 = { \sec}^{2} x

We take the LHS and simplify to arrive at the RHS.

{ \tan}^{2} x + 1 =  \frac{{ \sin}^{2} x}{{ \cos}^{2} x}  + 1

Collect LCM on the right hand side to get;

{ \tan}^{2} x + 1 =  \frac{{ \sin}^{2} x + {\cos}^{2} x}{{ \cos}^{2} x}

This implies that

{ \tan}^{2} x + 1 =  \frac{1}{{ \cos}^{2} x} .

{ \tan}^{2} x + 1 =  {( \frac{1}{ \cos(x) }) }^{2}

{ \tan}^{2} x + 1 =  { \sec}^{2} x

This identity has been verified .Therefore the correct answer is true.

3 0
2 years ago
21. In 4 + In(4x - 15) = In(5x + 19)
Alexxx [7]

Answer:

x=-30;\quad \:I\ne \:0

Step-by-step explanation:

In\cdot \:4+In\left(4x-15\right)=In\left(5x+19\right)

\:4+In\left(4x-15\right):\quad -11nI+4nxI\\In\cdot \:4+In\left(4x-15\right)\\=4nI+nI\left(4x-15\right)\\\\\:In\left(4x-15\right):\quad 4nxI-15nI\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\a=In,\:b=4x,\:c=15\\=In\cdot \:4x-In\cdot \:15\\=4nxI-15nI\\=In\cdot \:4+4nxI-15nI\\\mathrm{Simplify}\:In\cdot \:4+4nxI-15nI:\quad -11nI+4nxI\\In\cdot \:4+4nxI-15nI\\\mathrm{Group\:like\:terms}\\=4nI-15nI+4nxI\\\mathrm{Add\:similar\:elements:}\:4nI-15nI=-11nI\\=-11nI+4nxI\\

\mathrm{Expand\:}In\left(5x+19\right):\quad 5nxI+19nI\\In\left(5x+19\right)\\=nI\left(5x+19\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=In,\:b=5x,\:c=19\\=In\cdot \:5x+In\cdot \:19\\=5nxI+19nI\\\\-11nI+4nxI=5nxI+19nI\\\\\mathrm{Add\:}11nI\mathrm{\:to\:both\:sides}\\-11nI+4nxI+11nI=5nxI+19nI+11nI\\Simplify\\4nxI=5nxI+30nI\\\mathrm{Subtract\:}5nxI\mathrm{\:from\:both\:sides}\\4nxI-5nxI=5nxI+30nI-5nxI\\\mathrm{Simplify}\\-nxI=30nI\\

\mathrm{Divide\:both\:sides\:by\:}-nI;\quad \:I\ne \:0\\\frac{-nxI}{-nI}=\frac{30nI}{-nI};\quad \:I\ne \:0\\\mathrm{Simplify}\\\frac{-nxI}{-nI}=\frac{30nI}{-nI}\\\mathrm{Simplify\:}\frac{-nxI}{-nI}:\quad x\\\frac{-nxI}{-nI}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}\\=\frac{nxI}{nI}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{xI}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=x\\\mathrm{Simplify\:}\frac{30nI}{-nI}:\quad -30\\\mathrm{Apply\:the\:fraction\:rule}:

\quad \frac{a}{-b}=-\frac{a}{b}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{30I}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=-30\\x=-30;\quad \:I\ne \:0

3 0
3 years ago
What is the slope of this graph?<br><br> −1/3<br><br> 3<br><br> 1/3<br><br> −3
FromTheMoon [43]
I'm assuming there is probably a graph that goes with this problem so here is all the info I can give you with the four choices: If it is -1/3, the line will go DOWN 1, over 3 (just count on the graph) If it is 3, the line will go UP 3, over 1 If it is 1/3, the line will go UP 1, over 3 And if it it -3, it will go DOWN 3, over 1 (If the slope is 3 or -3, it would be quite steep compared to a slope of 1/3 or -1/3) Hope that helps!
4 0
3 years ago
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