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Vaselesa [24]
3 years ago
8

-2.35 as a fraction or mixed number in simplest form

Mathematics
2 answers:
trasher [3.6K]3 years ago
8 0

To convert a mixed number to its lowest form, one needs to change the mixed number into an improper fraction and then reduce this improper fraction to the lowest possible fraction. To do these conversions, one needs to perform a few calculations. One also has to understand the definitions of "mixed number," "improper fraction" and "proper fraction."

Allisa [31]3 years ago
6 0
2.35 as a mixed number in simplest form would be 2 7/20
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Answer:

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Step-by-step explanation:

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3 0
3 years ago
Help on this sh*t from 2-6
zlopas [31]

Answer:

1. x = 15, y = 8

2. m∠MSN = 90°

3. x = 20

4. y = 9

5. x = 8, m∠PQS = 24, m∠SQR = 66

6. y = 15, m∠RPT = 55, m∠TPW = 35

Step-by-step explanation:

1. to solve for y

9y + 18 = 90

9y + 18 - 18 = 90 - 18

9y = 72

9y/9 = 72/9

y = 8

to solve for x

5x + x = 90

6x = 90

6x/6 = 90/6

x = 15

2. m∠MSN = 90°, because ∠MSN is a right angle, which is equal to 90

3. To find x

3x + 10 + x = 90

3x + x = 4x

4x + 10 = 90

4x + 10 - 10 = 90 - 10

4x = 80

4x/4 = 80/4

x = 20

4. To find y

7y - 3 + 3y + 3 = 90

7y + 3y = 10

-3 + 3 = 0

10y = 90

10y/10 = 90/10

y = 9

5. To find x

3x + 8x + 2 = 90

3x + 8x = 11x

11x + 2 = 90

11x + 2 - 2 = 90 -2

11x = 88

11x/11 = 88/11

x = 8

To find ∠PQS

∠PQS = 3x

x = 8

so 3(x) = 3(8)

3(8) = 24

so ∠PQS = 24

To find ∠SQR

∠SQR = 8x + 2

x = 8

so ∠SQR = 8(x) + 2 = 8(8) + 2

8(8) + 2

= 64 + 2

= 66

6. To find y

4y - 5 + 2y + 5 = 90

4y + 2y = 6y

-5 + 5 = 0

6y = 90

6y/6 = 90/6

y = 15

To find ∠RPT

∠RPT = 4y - 5

y = 15

so ∠RPT = 4y - 5 = 4(15) - 5

4(15) - 5

= 60 - 5

= 55

To find ∠TPW

∠TPW = 2y + 5

y = 15

so ∠TPW = 2y + 5 = 2(15) + 5

2(15) + 5

= 30 + 5

= 35

7 0
3 years ago
Students conducted a study of different sized containers and found that the box shown held 240 blocks. What is the empirical rat
N76 [4]

Answer:

  B.  2 blocks per cubic inch

Step-by-step explanation:

The volume in cubic inches is the product of the dimensions in inches. The ratio of blocks per cubic inch is found by dividing the number blocks by the number of cubic inches. (Effectively, "per" means "divided by".)

  (240 blocks)/((6 in)(4 in)(5 in)) = 240/120 blocks/in³ = 2 blocks/in³

4 0
3 years ago
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7 0
3 years ago
A fish tank initially contains 10 liters of pure water. Brine of constant, but unknown, concentration of salt is flowing in at 4
Naddik [55]

Answer:

a) dx/dt = 4*c - (4*x / 10) = 4*c - 0.4*x

b) x = 10*c - 10*c*e^(-0.4*t)

c)  c = 2.500 g / Liters

Step-by-step explanation:

Given:

- Initial volume of pure water V_o = 10 Liters

- Inflow of brine Q_in = 4 Liters / min

- Outflow of mixture Q_out = 4 liters /min

Find:

a) Find a formula for the rate of change in the amount of salt, dx/dt, in terms of the amount of salt in the solution x and the unknown concentration of incoming brine c.

b) Find a formula for the amount of salt, in grams, after t minutes have elapsed. Your answer should be in terms of c and t.

c) In 25 minutes there are 25 grams of salt in the fish tank. What is the concentration of salt in the incoming brine?

Solution:

- We will define a constant (c) as concentration of salt as amount of salt in grams per liter.

- dx / dt is the amount of salt in grams per unit time t.

- We will construct a net flow balance:

                                dx / dt = Q_in*c - (amount of salt / V_o) *Q_out

- Denoting the amount of salt in grams to be x. then we have:

                                dx/dt = 4*c - (4*x / 10) = 4*c - 0.4*x

- Once we have formulated the ODE, we will solve it to get the amount of salt x in grams at any time t, as follows:

                               dx/dt = 4*c -0.4*x

- Separate variables:

                             dx / (4*c -0.4*x) = dt

- Integrate both sides:

                             - (10 / 4)*Ln | 4*c -0.4*x | = t + K

- Evaluate constant K, when t = 0, x = 0.

                               - (10 / 4)*Ln|4c| = K

- Input constant K back in solution:

                                  Ln |4*c -0.4*x| = -0.4*t + Ln|4c|

                                  4*c -0.4*x = 4c*e^(-0.4*t)

                                   x = 10*c - 10*c*e^(-0.4*t)

- Evaluate using the derived expression t = 25 mins and x = 25, compute c?

                                   x = 10*c - 10*c*e^(-0.4*t)

                                   25/10 = c ( 1 - e^(-0.4*25) )

                                    c = 2.5 / ( 1 - e^(-0.4*25) )

                                    c = 2.500 g / Liters

5 0
4 years ago
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