Question

Need HELP ASAP!!!!!!

Answer 1

Answer:

The variation equation is

$f = \frac{k.m_1.m_2}{ {r}^{2} }$

step-by-step explanation:

From the question, the two masses are

$m_1 \: and \: m_2$

This implies that the product of the two masses

$= m_1 \times m_2 = m_1.m_2$

Moreover, the force,f varies directly with the products of the two masses

$\implies \: f\propto m_1.m_2....eqn.1$

Also, the force varies inversely with the square of the distance,r

$\implies \: f\propto \frac{1}{ {r}^{2} }.......eqn.2$

Joining equation 1 and 2, we got

$\implies \: f\propto \frac{1}{ {r}^{2}} \times m_1.m_2$

$\implies \: f \propto\frac{m_1.m_2}{ {r}^{2}}$

But the constant of variation is k

Multiplying the right hand side of the equation by k, we got

$\implies \:f=\frac{k.m_1.m_2}{ {r}^{2}}$