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Sliva [168]
3 years ago
11

Find two consecutive odd integers such that seven times the first equals five times the second.

Mathematics
1 answer:
fredd [130]3 years ago
8 0

Answer:

Odd integers are always one more that an even integer:

1st: 2n+1

2nd: 2n+3

Step-by-step explanation:

14n+7 = 10n+15

4n = 8

n = 2

------------

1st: 2n+1 = 5

2nd: 2n+3 = 7

7x=5*(x+2)

7x=5x+10

7x-5x=10

2x=10

x=5

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14 is the GCF of anumber M and 210. What are possible values of M?
Cloud [144]
<span>14 = GCF of M and 210
M = possible values

GCF = Greatest common denominator
Now, let’s start decomposing
=> 210 | 2
=> 105 | 2
=>  35 | 5
=> 7 | 7
=> 1

Thus, 2 x 3 x 5 x 7 = 210

Now let’s find the factors of 14
=> 14 | 2
=> 7 | 7
=> 1

Thus, 2 x 7 = 14

Notice that’s there’s no 14 in 210 shown factors, but the only GCF found is 7.
Thus, the value of M that we’re looking for is infinite. All numbers that has the GCF of 7 are applicable.</span>



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3 years ago
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Doss [256]

Given that,

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To find,

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Solution,

We have,

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4 0
2 years ago
Which linear inequality is represented by the graph?
zheka24 [161]

Answer:

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Step-by-step explanation:

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Hello! Can you help you can get more points! Click on the photo for more view etc.
Murrr4er [49]

Answer:

22,950

Step-by-step explanation:

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