Find two consecutive odd integers such that seven times the first equals five times the second.
1 answer:
Answer:
Odd integers are always one more that an even integer:
1st: 2n+1
2nd: 2n+3
Step-by-step explanation:
14n+7 = 10n+15
4n = 8
n = 2
------------
1st: 2n+1 = 5
2nd: 2n+3 = 7
7x=5*(x+2)
7x=5x+10
7x-5x=10
2x=10
x=5
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