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3 years ago

15

The jubin in family is going to wacky world.They need $5496 to pay for their entire trip.If they have a year to save up for the

trip,how much money do they need to put away each month in order to have enough?

1 answer:

OLEGan [10]3 years ago

4 0

They need to put away $458 each month!

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The sum of 3 consecutive even

aleksandrvk [35]

Answer:

The variable representation is x, x+2 and x+4 for this sequence.

Step-by-step explanation:

Given that:

The sum of 3 consecutive even numbers is 78.

Let,

The first even number is represented by x.

As the numbers are consecutive, thus,

First even number = x

Second even number = x+2

Third even number = x+4

Hence,

The variable representation is x, x+2 and x+4 for this sequence.

7 0

2 years ago

A standard weight known to weigh 10 grams. Some suspect bias in weights due to manufacturing process. To assess the accuracy of

notsponge [240]

Answer:

a) The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams

b) 49 measurements are needed.

Step-by-step explanation:

Question a:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.98}{2} = 0.01$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.01 = 0.99$ , so Z = 2.327.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.327\frac{0.0003}{\sqrt{5}} = 0.00031$

The lower end of the interval is the sample mean subtracted by M. So it is 10.0044 - 0.00031 = 10.00409 grams

The upper end of the interval is the sample mean added to M. So it is 10 + 0.00031 = 10.00471 grams

The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams.

(b) How many measurements must be averaged to get a margin of error of +/- 0.0001 with 98% confidence?

We have to find n for which M = 0.0001. So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.0001 = 2.327\frac{0.0003}{\sqrt{n}}$

$0.0001\sqrt{n} = 2.327*0.0003$

$\sqrt{n} = \frac{2.327*0.0003}{0.0001}$

$(\sqrt{n})^2 = (\frac{2.327*0.0003}{0.0001})^2$

$n = 48.73$

Rounding up

49 measurements are needed.

7 0

3 years ago

Which of these is a step in constructing an inscribed equilateral triangle using technology?

lyudmila [28]

I think that the answer is B. I tried to read more about the question to understand it more but got nothing out of it.

5 0

3 years ago

HURRY PLEASE Which function is the inverse of f(x) = -5x – 4?

vagabundo [1.1K]

Answer:

f^-1(x)= -x/5 - 4/5

Step-by-step explanation:

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2 years ago

Jamel watched his older brother Robert lift weights. The bar alone had a mass of 20 kg. On the bar he had tow 11.4 kg weights, t

slavikrds [6]

All you do is add them all together...
20 + 11.4 + 11.4 + 4.5 + 4.5 + 0.45 + 0.45 + 0.45 + 0.45 = 53.6Kg
(note that 0.45 is 450g in Kg, When adding things such as weight or length you want to make sure that they are all in the same unit)

6 0

3 years ago