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marusya05 [52]
4 years ago
7

What's the probability you roll the same number twice on a regular dice?

Mathematics
1 answer:
jekas [21]4 years ago
4 0
1/6 because the first number that you roll doesn't matter so it depends on the 2nd roll, in which the probability of rolling a specific number is 1/6
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In our hall, there are 10 fans, but only 60% of them are working. Write the number of fans that are out of order?! Pls answerr I
Natali [406]

Answer:

6

Step-by-step explanation:

There's 10 fans, so each is worth 10%

If 60% of them are not working, that means that 6 fans are not working.

10 - 6 = 4

There are 6 not working fans

and there are 4 working fans

3 0
3 years ago
Finding the Midpoint of the Two Coordinates<br> 6.) A(-2, 3), B(5,-1)
RoseWind [281]

Answer:

The answer is

<h2>( \frac{3}{2}  \: , \: 1) \\</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

M = (  \frac{x1 + x2}{2} , \:  \frac{y1 + y2}{2} )\\

From the question the points are

A(-2, 3), B(5,-1)

The midpoint is

M = ( \frac{ - 2 + 5}{2} \:   , \:  \frac{3 - 1}{2} ) \\   = ( \frac{3}{2}  \: , \:  \frac{2}{2} )

We have the final answer as

( \frac{3}{2}  \: , \: 1) \\

Hope this helps you

8 0
3 years ago
Benford's law states that in a very large variety of real-life data sets, the first digit approximately follows a particular dis
Elden [556K]

Answer:

Step-by-step explanation:

6 0
3 years ago
A marathon runner ran the first 4 mi
Roman55 [17]

Step-by-step explanation:

4 miles / 27.8 min = 0.14388 miles per minute

26.2 / 0.143888 = 182.1 min

5 0
4 years ago
Read 2 more answers
A bag contains 1 red, 3 green, and 5 yellow balls. A sample of four balls is picked. Let G be the number of green balls in the s
Citrus2011 [14]

Answer:

P(Y=r) = 4Cr (5/9)^r (4/9)^{4-r},r=0,1,2,3,4

Step-by-step explanation:

Given that a bag contains 1 red, 3 green, and 5 yellow balls. A sample of four balls is picked, with replacement

When balls are picked with replacement, each time the ball picked up does not depend on the previous outcomes.

Thus given y=2 will not affect the pdf of G

In G, Y no of yellow balls can take values as 0,1,2,3,4

Prob of drawing a yellow ball each time = 5/9

Y = no of yellow balls is binomial with n =4 and p = 5/9

P(Y=0) = (1-5/9)^4 = (\frac{4}{9} )^4

In general,

P(Y=r) = 4Cr (5/9)^r (4/9)^{4-r},r=0,1,2,3,4

7 0
4 years ago
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