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prohojiy [21]
2 years ago
13

[-x - 2y = 7 [3x + y = 6

Mathematics
1 answer:
ZanzabumX [31]2 years ago
8 0

Answer:

multipling \: eq \: by \: 3 \\ then \: we \: get \:  - 3x - 6y = 21 \\ now \: add \: both \: eq \\   - 5y = 27 \\ y =  - 5.4

Step-by-step explanation:

plz.......

mark it as a brilliant answer

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Answer:

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Step-by-step explanation:

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Find the Volume of the shape below.<br> 4 ft<br> 2 ft<br> 2 ft
erma4kov [3.2K]

Answer:

16 ft³

Step-by-step explanation:

4ft x 2ft x 2ft = 4ft x 4ft = 16 ft³

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Ranboo gave tubbo bees. 3/4 of the bees were black, 1/ 8 of the bees were yellow, and the rest were both how many bees are both
uysha [10]
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5 0
2 years ago
How to solve this ? I am not sure pls if you know the answer answer it I really neeed it for marks
xz_007 [3.2K]

Answer:

L.S = R.S ⇒ Proved down

Step-by-step explanation:

Let us revise some rules in trigonometry

  1. sin²α + cos²α = 1
  2. sin2α = 2 sin α cosα
  3. cscα = 1/sinα

To solve the question let us find the simplest form of the right side and the left side, then show that they are equal

∵ L.S = csc2α + 1

→ By using the 3rd rule above

∴ L.S = \frac{1}{sin2\alpha} + 1

→ Change 1 to \frac{sin2\alpha}{sin2\alpha}

∴ L.S = \frac{1}{sin2\alpha} + \frac{sin2\alpha}{sin2\alpha}

→ The denominators are equal, then add the numerators

∴ L.S = \frac{1+sin2\alpha}{sin2\alpha}

∵ R. S = \frac{(sin\alpha+cos\alpha)^{2} }{sin2\alpha}

∵ (sinα + cosα)² = sin²α + 2 sinα cosα + cos²α

∴ (sinα + cosα)² = sin²α + cos²α + 2 sinα cosα

→ By using the 1st rule above, equate sin²α + cos²α by 1

∴ (sinα + cosα)² = 1 + 2 sinα cosα

→ By using the 2nd rule above, equate 2 sinα cosα by sin2α

∴ (sinα + cosα)² = 1 + sin2α

→ Substitute it in the R.S above

∴ R. S = \frac{1+sin2\alpha}{sin2\alpha}

∵ L.S = R.S

∴ csc 2α + 1 = \frac{(sin\alpha+cos\alpha)^{2} }{sin2\alpha}

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3 years ago
Find the probability of choosing a blue marble at random from a bag of 5 blue and 5 green marbles and then flipping a coin and g
RUDIKE [14]
I think the answer is b. 1/3 but I might be wrong
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