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oksian1 [2.3K]
3 years ago
13

Criminal investigators use biometric matching for fingerprint recognition, facial recognition, and iris recognition. When matchi

ng fingerprints, each subject is given a mean match score for how well their fingerprint matches the given fingerprint, based on different criteria. There are six criteria used to calculate the match score. The mean match score used by a particular police department is 80. If the police department finds a higher match score than this number, they consider the person a fingerprint match and a suspect in the crime. The null hypothesis is that the mean match score is 80. The alternative hypothesis is that the mean match score is greater than 80. Is the following a Type I error or a Type II error or neither? The test shows that the mean match score is more than 80 when the person does not actually have a fingerprint match. Group of answer choices Type I error Type II error
Mathematics
1 answer:
Daniel [21]3 years ago
6 0

Answer:

Type I error.

Step-by-step explanation:

Let's remember the definition of Type I error and Type II error:

A type I error is the rejection of a true null hypothesis, this means that we would get a "false positive" with this error.

A type II error is the non rejection of a not true null hypothesis, this error would give us a "false negative".

In this problem, we are told that the mean match score to identify a suspect is 80. However, the test shows that the mean match score is more than 80 when the person doesn't have a fingerprint match (and therefore the person would not be a suspect). Therefore, this person would appear as a suspect when he/she really isn't one. This means that the test is giving a "false positive". Thus, this is a type I error.

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He lost 8, so he is at -8, he then gains 15 so add 15 to -8"-8 + 15 = 7

He gains 7 so now add 7 to the total: 7+ 7 = 14

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2 years ago
How would you write odds in favor?
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Answer: Odds in favor = Number of successes: Number of failures

Step-by-step explanation:

Example

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3 years ago
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Step-by-step explanation:

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(look at the images) can i get help on these?
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see explanation

Step-by-step explanation:

15

JK + KL = JL , substitute values

2x + 1 + 6x = 81, that is

8x + 1 = 81 ( subtract 1 from both sides )

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x = 10

Thus JK = 2x + 2 = 2(10) + 1 = 20 + 1 = 21

KL = 6x = 6 × 10 = 60

--------------------------------------------------------------

16

JK + KL = JL , substitute values

2x + x + 2 = 5x - 10 , that is

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2 = 2x - 10 ( add 10 to both sides )

12 = 2x ( divide both sides by 2 )

6 = x

Thus

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KL = x + 2 = 6 + 2 = 8

JL = 5x - 10 = 5(6) - 10 = 30 - 10 = 20

------------------------------------------------------------

17

Calculate the distance d using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = S(7, 3) and (x₂, y₂ ) = T(1, - 5)

d = \sqrt{(1-7)^2+(-5-3)^2}

   = \sqrt{(-6)^2+(-8)^2}

   = \sqrt{36+64}

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3 years ago
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