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Aleks04 [339]
3 years ago
8

Mr. Rodriguez, a college instructor, can grade his class papers in 3 hours while it takes his assistant 4 1 2 hours. If Mr. Rodr

iguez graded the papers for 1 hour and then left the job for his assistant to complete, how long will it take his assistant to finish grading papers?
Mathematics
1 answer:
const2013 [10]3 years ago
6 0

Answer:

  3 hours

Step-by-step explanation:

Rodriguez did 1/3 of the job, so the remaining 2/3 of the job will take the assistant 2/3 of the usual time:

  (2/3)(4 1/2) = 3 . . .  hours

The assistant can complete the job in 3 hours.

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Ok, I would really like some help ^.^ If you could and have the time...would you mind breaking down the answer for me please, he
uysha [10]

Answer:

C

Step-by-step explanation:

4 x 4=16 and half of 4 is 2 so the answer is C)4

5 0
3 years ago
Read 2 more answers
A pole-vaulter uses a 15-foot-long pile. She grips the pole so that the segment below her left hand is twice the length of the s
Shalnov [3]
Let x + 1.5 be length of segment above left hand
Let 2x be length of segment below left hand

15 = x + 1.5 + 2x
15 = 3x + 1.5
15 - 1.5 = 3x
13.5 = 3x
13.5/3= 3x/3 
4.5 = x
x = 4.5
This is the length above the left hand. 

2x must be then 4.5*2 = 9 foot
This is the length below the left hand. 

Checking
4.5 + 9 + 1.5 = 15 foot 

Adding length below left hand & length of left hand to right hand:
9 + 1.5 = 10.5
The right hand is hence 10.5 foot far up the pole.
6 0
3 years ago
A survey of 340 randomly chosen US adults found that 60% of the 150 men and 50% of the 190 women ran a five-kilometer race durin
Andrej [43]

Answer:

The p-value is less than the significance level, so we will reject the null hypothesis, and conclude that at 5% significance level, the proportion for women that ran 5 km is more than the proportion of male that ran the 5 km. Thus, women are more likely to run the 5 km race.

Step-by-step explanation:

We are given;

Number of males selected; n₁ = 150

Number of females selected; n₂ = 190

Proportion of the males; p₁ = 0.6

Proportion of females; p₂ = 0.5

Let's define the hypotheses;

Null hypothesis; H0: p₁ ≥ p₂

Alternative hypothesis; Ha: p₁ < p₂

Now, the z score formula for this is;

z = (p₁ - p₂)/√(p^(1 - p^))(1/n₁ + 1/n₂))

Where;

p^ = (p₁ + p₂)/2

p^ = (0.6 + 0.5)/2

p^ = 0.55

Thus;

z = (0.6 - 0.5)/√(0.55(1 - 0.55))((1/150) + (1/190))

z = 0.1/0.0543

z = 1.84

From online p-value from z-score calculator attached, using z = 1.84, significance level = 0.05, one tailed hypothesis, we have;

P-value = 0.033

The p-value is less than the significance level, so we will reject the null hypothesis, and conclude that at 5% significance level, the proportion for women that ran 5 km is more than the proportion of male that ran the 5 km. Thus, women are more likely to run the 5 km race.

Although if we check at 0.01 significance level, we will not have the same answer as the p-value will be greater.

3 0
3 years ago
1<br> Enter the correct answer in the box.<br> Simplify the expression (62,4.
adelina 88 [10]

Answer:

248

Step-by-step explanation:

(62)4

= 62 x 4

= 248

4 0
2 years ago
Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t
NISA [10]

Answer:

Class second have higher score and have greater spread.

Step-by-step explanation:

For first box plot

\text{Minimum value }= 53

Q_1=62

Median=80

Q_3=86

\text{Maximum value }= 89

Range=Maximum-Minimum=89-53=36

IQR=Q_3-Q-1=86-62=24

For second box plot

\text{Minimum value }= 56

Q_1=62

Median=74

Q_3=89

\text{Maximum value }= 96

Range=Maximum-Minimum=96-56=40

IQR=Q_3-Q-1=89-62=27

First class has greater minimum value, it means first class has lower grades.

First quartile of both classes are same, it means equal number students in both classes have less than 62 marks.

First class has greater median.

second class has greater third quartile.

Second class has greater Maximum value.  It means second class have higher score than first class.

Second class has greater range. It means the data of second class has greater spread.

Second class has greater inter quartile range.  It means the data of second class has greater spread.

Therefore, the class second have higher score and have greater spread.

5 0
3 years ago
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