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Mrrafil [7]
4 years ago
9

What type of microscope requires a nonmetal sample to be prepared for viewing by coating it with a thin layer of a conductive ma

terial?
Computers and Technology
2 answers:
dezoksy [38]4 years ago
7 0
<span>Scanning electron microscope All non-metals need to be made conductive by covering the sample with a thin layer of conductive material</span>
zheka24 [161]4 years ago
5 0

The answer is a Scanning Electron Microscope

It is important to obtain and prepare proper samples when using SEM. The sample’s size, state, and shape are things that should be considered before the sample preparation. Some samples need to be coated. Most metals require no preparation since they can easily conduct electricity. Non-metals, however, needs to be coated with a thin layer of gold. Gold is the ideal non-metal and works most of the times.

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You are configuring a wireless network with two wireless access points. Both access points connect to the same wired network. Yo
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Answer:

b. Same SSID, different channel

Explanation:

The Service Set Identifier (SSID) is a sequence that is included in all of the sets in a wirless network and helps identify them as part of the network. Because both points connec to the same network they need the same SSID.

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3 years ago
_________ devices often pose special challenges to investigators because they can be configured to use advanced encryption and t
scoray [572]

Answer:

Portable

Explanation:

Most of electronic devices can be programmed in a way that cant deny investigator access to certain information on the device and also, devices can be manipulated by an external hands to implicate people.

due to those uncertainty, some states place little wait on evidences obtained from those devices.

4 0
3 years ago
Megan was employed by a large company. Her supervisor told her to falsify government reports. She refused and was fired. She sue
Ber [7]

Answer: Option(d) is correct option

Explanation:

At-will employment is the employment in contractual manner in which employer can fire employee without any warning or indication .They can fire employee for any cause .

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  • Other options are incorrect because employer was not correct on firing her because of loyalty duty or based on legal right or with just reason.Thus, the correct option is option(d)
7 0
4 years ago
What kind of negative social impact has wireless communications had on today's society?
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5 0
4 years ago
Read 2 more answers
Modify the CharacterInfo class shown in Figure 7-3 so that the tested character is retrieved from user input.
nata0808 [166]

The tested character is modified as given below. See the definition of tested character below.

<h3>What is characterization testing?</h3>

Michael Feathers created the phrase "characterization testing."

A characterization test (also known as Golden Master Testing) in computer programming.

It is a method of describing (characterizing) the actual behavior of an existing piece of software and thereby protecting legacy code against unwanted modifications through automated testing.

<h3>What is the modified characterInfo class?</h3>

Run on java, the modified characterInfo class is given as follows:

//import packages

import java.util.Scanner;

//Java class

public class InputCharacterInfo {

   //entry point of the program , main method

   public static void main(String[] args) {

       //creating object of Scanner class

       Scanner sc=new Scanner(System.in);

       //asking user to enter character

       System.out.print("Enter a character : ");

       //reading character

       char aChar=sc.next().charAt(0);

       System.out.println("The character is "+aChar);

       if(Character.isUpperCase(aChar))

           System.out.println(aChar+" is uppercase");

       else

           System.out.println(aChar+" is not uppercase");

       if(Character.isLowerCase(aChar))

           System.out.println(aChar+" is lowercase");

       else

           System.out.println(aChar+" is not lowercase");

       aChar=Character.toLowerCase(aChar);

           System.out.println("After toLowerCase(), aChar is "+aChar);

       aChar=Character.toUpperCase(aChar);

           System.out.println("After toUpperCase(), aChar is "+aChar);        

   }

}

Learn more about characterization testing in programming at;
brainly.com/question/13142406
#SPJ1

8 0
2 years ago
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