Answer:
The correct answer for the given question is "The program has a runtime NullPointerException because test is null while executing test.x"
Explanation:
In this code their is run time exception will occur in Main method i.e "java.lang.NullPointerException "because the object of the Test class i.e test will initialized by "null" .So on executing the statement test.x it gives an Runtime Exception.The "NullPointerException" can occur if we assign the object to the "null" value that why it produce an java.lang.NullPointerException
Answer A is the answer, as it combines all choices in the list. One can check the overall structure.
Over a TCP connection, suppose host A sends two segments to host B, host B sends an acknowledgement for each segment, the first acknowledgement is lost, but the second acknowledgement arrives before the timer for the first segment expires is True.
True
<u>Explanation:</u>
In network packet loss is considered as connectivity loss. In this scenario host A send two segment to host B and acknowledgement from host B Is awaiting at host A.
Since first acknowledgement is lost it is marked as packet lost. Since in network packet waiting for acknowledgement is keep continues process and waiting or trying to accept acknowledgement for certain period of time, once period limits cross then it is declared as packet loss.
Meanwhile second comes acknowledged is success. For end user assumes second segments comes first before first segment. But any how first segment expires.
