Answer: (a) 9
Step-by-step explanation:
We are given that ,
The first two classes of a frequency distribution are 0-9 and 10-19.
We know that the class width of an class interval is basically the difference between the upper limit and the lower limit of the interval.
For example the class interval for interval 40 - 45 is 5 because 45-40=5.
For the given class interval 0-9 , upper limit= 9
Lower limit =0
⇒ Class width = 9-0= 9
Similarly , for 10-19 , the class width = 19-10=9
Therefore , the class width is 9 .
Hence, the correct answer is (a) 9.
In this equation the q is 12/17 and the r is 3/8 so if I am correct the answer is 9/34 hope this helps.
With the given speed and the time traveled, we can solve for the distance by using the distance formula: distance = speed x time:
Substituting the given values to the equation:
d = 61 <span>• 4
Among the choices, the correct answer is C.</span>
LMNO is a parallelogram ⇒ LP=NP
6x-5=4x+17
2x=22
x=11
LP=6*11-5=61 cm
NP=4*11+17=61 cm
LP=PN=61 cm
LN=122 cm
Answer:
(a)
Step-by-step explanation:
To determine if the points are a solution to the equation.
Substitute the coordinates of the point into the left side of the equation and if equal to the right side then they are a solution.
(2, 5)
- 3(2) + 4(5) = - 6 + 20 = 14 ← True
(4, 6)
- 3(4) + 4(6) = - 12 + 24 = 12 ← False
Thus (2, 5) is the only solution to the equation → (a)
