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Aleks04 [339]
3 years ago
7

After how many seconds is the height 68 feet? When the equation is h=-16t2+64t+8

Mathematics
1 answer:
Rudiy273 years ago
5 0
<span>68=-16t2+64t+8
16t2-64t+60=0

4t2-16t+15=0
(2t-5)(2t-3)=0
t=5/2 or 3/2
The object is at 68 feet after 3/2 secs, and returns to 68 feet after another second..</span>
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Solving by elimination <br> 5x+2y= -3<br> 3x+3y=9<br> please help me solve x and y
-Dominant- [34]
1) -3(5x+2y=-3)⇒ -15x-6y=9
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2) -9x/-9=27/-9 ⇒ x=-3 

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Answer: (-3,6)

Reasoning:
Step 1) In order to eliminate, first I had to multiple the first equation by -3 and the second by 2 so that when combining the equations y would cancel each other out so that I could solve for x. <em>Note: There are many combinations as to how you could multiple the equations so that either the x or y would cancel out.
</em>
Step 2) Once y is eliminated, solve for x.

Step 3) Now plug x back into one of the original equations and solve for y. <em>Note: Plug x back into one of the original equations, not the equations that were changed by multiplication,</em> 

6 0
3 years ago
F (x) = |x + 3| -1 . Find the average rate of change from x = -6 to x = 8
Elenna [48]
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3 years ago
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Ket [755]
9x-4/x=3 ok first lets get the like terms together! So 9x+1x=10x rewrite 10x-4=3 add 4 to both sides 10x=7 then divide 10 7/10=.7 x=.7
Or you can do it this way
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