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Aleks04 [339]
3 years ago
7

After how many seconds is the height 68 feet? When the equation is h=-16t2+64t+8

Mathematics
1 answer:
Rudiy273 years ago
5 0
<span>68=-16t2+64t+8
16t2-64t+60=0

4t2-16t+15=0
(2t-5)(2t-3)=0
t=5/2 or 3/2
The object is at 68 feet after 3/2 secs, and returns to 68 feet after another second..</span>
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An airplane flies due north from ikeja airport for 500km.It then flies on a bearing of 060 from a further distance of 300km befo
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Answer:

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Cosine rule states that

C = \sqrt{A^{2} + B^{2} -2AB   cos(c)  }

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C = \sqrt{500^{2} + 300^{2} -2 * 500 * 300 cos(60)  }

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The bearing can be gotten by using the Sine Rule.

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3 years ago
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