How can we reduce the ripple factor of a bridge recitifier from 0.48 to 0.1 approximately ?
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Answer:
The value of capillary rise in the tube = 0.0363 cm
Explanation:
Diameter of the glass tube = 0.03 meter
Contact angle = 22 degree
We know that the capillary rise (h) in the tube is given by the formula =
h = (2 α cos β) / (d g R )
⇒ d = density of gasoline = 749 kg /
β = 22 degree
R = radius of the tube = 0.015 m
α = surface tension of gasoline = 0.0216 N / m
cos 22 = 0.927
Put all the values in the above formula we get
⇒ h = (2 × 0.0216 × 0.927) / (749 × 9.81 × 0.015)
⇒ h = 0.0363 cm
This is the value of capillary rise in the tube.