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Juli2301 [7.4K]
3 years ago
15

In addition to the sources of error mentioned above, since the caliper jaws squeezed the flexible, rubber surface of the ball sl

ightly, the measured diameters were slightly __________________ compared to what a non-contact method of measuring would provide. This represents an ________________ ________________ error in ________________. This additional source of error ________________ ________________ significant. When the caliper jaws closed, the zero mark on the sliding Vernier scale, ________________ line up with the zero mark on the measuring scale. This means the caliper ________________ calibrated correctly.
Physics
1 answer:
VLD [36.1K]3 years ago
7 0

Answer:

MINORS,    SYSTEMATIC,   STATISTICAL,  BOTOM LINE, ZERO MATCHES

Explanation:

In general the sources of error or uncertainty can be classified

* Statistics. Which are those that describe the statistical formulas, for example: average, standard deviation, absolute error, etc.

* Systematic. That they occur due to an inappropriate measurement or to an interaction between the system and the instrument that cannot be quantified, in general this error shifts the measurements towards an explicit side

* Random, so errors that sometimes occur in the measurement and sometimes not, for example temperature changes during the medical process

In this case, you are asked to complete the sentences with the appropriate word

the measured diameters were slightly ___ MINORS________ compared to what a non-contact method of measuring would provide

. This represents an ____SYSTEMATIC_______ error in ________________.

This additional source of error ________STATISTICAL________ significant.

When the caliper jaws closed, the zero mark on the sliding Vernier scale, BOTOM LINE AND THE __________ line up with the zero mark on the measuring scale.

This means the caliper ___ZERO MATCHES_____________ calibrated correctly.

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V^2 = 2Ek / m — plug in values

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3 years ago
What is the kinetic energy of an object moving 40m/s with a mass of 20kg?
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5 0
2 years ago
A Carnot engine whose high-temperature reservoir is at 464 K has an efficiency of 25.0%. By how much should the temperature of t
nexus9112 [7]

Answer

given,

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efficiency  of reservoir (ε)= 25 %

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increase in efficiency = 42 %

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now,

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