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Juli2301 [7.4K]
3 years ago
15

In addition to the sources of error mentioned above, since the caliper jaws squeezed the flexible, rubber surface of the ball sl

ightly, the measured diameters were slightly __________________ compared to what a non-contact method of measuring would provide. This represents an ________________ ________________ error in ________________. This additional source of error ________________ ________________ significant. When the caliper jaws closed, the zero mark on the sliding Vernier scale, ________________ line up with the zero mark on the measuring scale. This means the caliper ________________ calibrated correctly.
Physics
1 answer:
VLD [36.1K]3 years ago
7 0

Answer:

MINORS,    SYSTEMATIC,   STATISTICAL,  BOTOM LINE, ZERO MATCHES

Explanation:

In general the sources of error or uncertainty can be classified

* Statistics. Which are those that describe the statistical formulas, for example: average, standard deviation, absolute error, etc.

* Systematic. That they occur due to an inappropriate measurement or to an interaction between the system and the instrument that cannot be quantified, in general this error shifts the measurements towards an explicit side

* Random, so errors that sometimes occur in the measurement and sometimes not, for example temperature changes during the medical process

In this case, you are asked to complete the sentences with the appropriate word

the measured diameters were slightly ___ MINORS________ compared to what a non-contact method of measuring would provide

. This represents an ____SYSTEMATIC_______ error in ________________.

This additional source of error ________STATISTICAL________ significant.

When the caliper jaws closed, the zero mark on the sliding Vernier scale, BOTOM LINE AND THE __________ line up with the zero mark on the measuring scale.

This means the caliper ___ZERO MATCHES_____________ calibrated correctly.

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A motorist drives south at 24.0 m/s for 3.00 min, then turns west and travels at 25.0 m/s for 2.20 min, and finally travels nort
grigory [225]

Answer:

magnitude m = 5440.26 M

average speed is = 25.05 m/s

average velocity = 14.62 m/s

Explanation:

given data

speed v1 = 24 m/s

time t1 = 3 min = 180 s

speed v2 = 25 m/s

time t2 = 2.2 min = 132 s

speed v3 = 30 m/s

time t3 = 1 min = 60 s

total time = 6.2 min = 372 s

to find out

displacement in m  and average speed and  average velocity

solution

so we find here displacement

displacement = vt    .............1

so

displacement 1 = 24 × 180 =  4220 m south = -4220 j   ..........2

displacement 2 = 25 × 132 = 3300 m west = -3300 i     ...........3

distance 3 = 30 × 60 =  1800 m

displacement   = 1800 cos45 -i + 1800 cos45 j

displacement   = -1272.79 i + 1272.79 j                             .............4

so total displacement D =  equation 2 + equation 3 + equation 4

total displacement D =  -4220 j -3300 i -1272.79 i + 1272.79 j

total displacement D =  -2947.21 j - 4572.79 i

so magnitude m = √(-2947.21)² + (-4572.79)² )

so magnitude m = 5440.26 M

and

average speed is = total distance / time

average speed is = (4220 + 3300+ 1800 ) / 372

average speed is = 25.05 m/s

and

average velocity = total displacement / time

average velocity = 5440.26 / 372

average velocity = 14.62 m/s

7 0
4 years ago
What is the relationship between the mass of an object and the amount of force required to drag it across the table?
hammer [34]

Answer:

Force = mass × acceleration

Explanation:

The amount of force required to drag the object across the table is the product of the mass of the object and acceleration

6 0
3 years ago
What net force would be required for a 50.5 kg wolf to accelerate at 5.0 m/s^2
Basile [38]

Answer:

\boxed {\boxed {\sf 252.5 \ Newtons }}

Explanation:

Force is the push or pull on object that can cause different things, like acceleration. According to Newton's 2nd Law of Motion, it is the product of mass and acceleration.

F=m*a

The mass of the wolf is 50.5 kilograms and the acceleration is 5.0 meters per square second. Therefore:

  • m= 50.5 \ kg
  • a= 5.0 \ m/s^2

Substitute the values into the formula.

F= 50.5 \ kg * 5.0 \ m/s^2

Multiply.

F=252.5 \ kg*m/s^2

  • 1 kilogram meter per square second is equal to 1 Newton.
  • Our answer of 252.5 kg*m/s² is equal to 252.5 Newtons.

F= 252.5 \ N

The force required is <u>252.5 Newtons</u>.

4 0
3 years ago
Anyone please ??? ASAP 15 points ???
Fed [463]

Answer:

1) you could put more force behind it. (increase) 2) have another object interact with that object. (increase or decrease) 3) the object could hit a wall and stop or slow down (decrease)

Sorry if wrong

5 0
3 years ago
The gravity of Neptune is about 1.1 times the gravity of Earth. How will the mass of an object on Neptune compare with its mass
irina1246 [14]

Gravity has an effect on weight, but not on mass. The mass of the object will be the same on both planets. (choice-C)

7 0
3 years ago
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