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givi [52]
3 years ago
12

SC.912.P.12.10

Physics
1 answer:
Korolek [52]3 years ago
8 0

Answer:

D

Explanation:

You can see the 1st Law thermodynamatic, that energy flow of thermo source.

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Starting at 1.0 m/s, a cheetah runs with a constant acceleration for 4.8 s reaching a speed of 28 m/s. What is the acceleration
LenaWriter [7]

Answer:

c.5.6m/s^2

Explanation:

Initial velocity of cheetah,u=1 m/s

Time taken by cheetah =4.8 s

Final velocity of cheetah,v=28 m/s

We have to find the acceleration of this cheetah.

We know that

Acceleration,a=\frac{v-u}{t}

Where v=Final velocity of object

u=Initial velocity of object

t=Time taken by object

Using the formula

Then, we get

Acceleration, a=\frac{28-1}{4.8}=\frac{27}{4.8} m/s^2

Acceleration=a=5.6 m/s^2

Hence, the acceleration of cheetah=5.6m/s^2

5 0
3 years ago
Singly charged gas ions are accelerated from rest through a voltage of 10.3 V. At what temperature (in K) will the average kinet
Natasha_Volkova [10]

Answer:

Temperature of the gas molecules is 7.96 x 10⁴ K

Explanation:

Given :

Ions accelerated through voltage, V = 10.3 volts

The work done to change the position of singly charged gas ions is given by the relation :

W = q x V

Here q is charge of the ions and its value is 1.6 x 10⁻¹⁹ C.

Average kinetic energy of gas molecules is given by the relation:

K.E. = \frac{3}{2}kT

Here T is temperature and k is Boltzmann constant and its value is 1.38 x 10⁻²³ J/K.

According to the problem, the average kinetic energy of gas is equal to the work done to move the singly charged ions, i.e. ,

K.E. = W

\frac{3}{2}kT = qV

Rearrange the above equation in terms of T :

T= \frac{2qV}{3k}

Substitute the suitable values in the above equation.

T=\frac{2\times1.6\times10^{-19}\times10.3 }{3\times1.38\times10^{-23} }

T = 7.96 x 10⁴ K

5 0
3 years ago
Total charge is uniformly distributed on a spherical surface of radius R. The sphere is centered at the origin and spins around
Flauer [41]

Answer:

c

Explanation:

i have a A in physics

5 0
3 years ago
A rod 25 cm long moves in a plane perpendicular to a magnetic field of 600 G. The velocity of the rod is perpendicular to its le
Airida [17]

Answer:

v = 666.667 m/s

Explanation:

<u>Given</u>: length L = 25 cm = 0.25 m,  B = 600 G =  0.06 T ( 1G = 0.0001 T)

emf= 10 V

Solution:

emf = vBL

v= emf / BL

v = 10 V / (0.06 T× 0.25 m)

v = 666.667 m/s

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3 years ago
Calculate the heat energy conducted per hour through the side walls of a cylindrical steel
Maru [420]

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