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3 years ago

9

the base of a pyramid is a square with 5 lines of 5cm the slant height of each lateral face of the pyramid is 6 cm what is the s

urface area of the pyramid

1 answer:

il63 [147K]3 years ago

5 0

Answer:

105.97

Step-by-step explanation:

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Solve the following system of equations:

Gnoma [55]

We have two equation with two unknowns. Therefore, we can solve the x and y easily. There are a number of methods to apply here but I will be using substitution method. We do as follows:

-2x + y = 1
y = 1 + 2x

4x + y = -1
4x + 1 + 2x = -1
6x = -1 -1
6x = -2
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Identify an equation in point-slope form for the line perpendicular to

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Answer:

$y - 9 = \frac{1}{2}(x +3)$

Step-by-step explanation:

Given

Function; $y = -2x + 8$

Required

Find an equation perpendicular to the given function if it passes through (-3,9)

First, we need to determine the slope of: $y = -2x + 8$

The slope intercept of an equation is in form;

$y = mx + b$

<em>Where m represent the slope</em>

Comparing $y = m_1x + b$ to $y = -2x + 8$ ;

We'll have that

$m_1 = -2$

Going from there; we need to calculate the slope of the parallel line

The condition for parallel line is;

$m_1 * m_2 = -1$

Substitute $m_1 = -2$

$(-2) * m_2 = -1$

Divide both sides by -2

$m_2 =\frac{ -1}{-2}$

$m_2 =\frac{1}{2}$

The point slope form of a line is;

$y - y_1 = m_2(x - x_1)$

Where $(x_1,y_1) = (-3,9)$ and $m_2 =\frac{1}{2}$

$y - y_1 = m_2(x - x_1)$ becomes

$y - 9 = \frac{1}{2}(x - (-3))$

Open the inner bracket

$y - 9 = \frac{1}{2}(x +3)$

<em>Hence, the point slope form of the perpendicular line is: </em>

<em /> $y - 9 = \frac{1}{2}(x +3)$ <em />

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3 years ago

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julsineya [31]

Answer:

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Step-by-step explanation:

6^-2 = 1/6^2

1/6^2 * 6^5 = 6^5/6^2 = 6^3

6^(3 * -3) = 6^-9= 1/6^9

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