There are a number of different problems that you could do that will give you an outcome of 9/10
For example, 1/2 and 2/5 add up to 9/10.
3/10 and 6/10 also add up to 9/10.
Find the sum of 7/10 and 1/5
Find the sum of 7/20 and 11/20
Find the sum of 1/2 and 3/10 and 1/10
Find the sum of 1/5 and 2/5 and 3/10
Hope this helps :)
F = kq2 / r2
q = ne
F = k(ne)2 / r2
n = âš(r2F / ke2) = (r/e) âš(F/k)
k = 9 x 109 Nm2/C2
e = 1.6 x 10-19 C
n = [(4.2 x 10-10) / (1.6 x 10-19)] âš[(5.2 x 10-9) / (9 x 109)] ≅ 1.995 ≅ 2
Diameter = 2*radius
14/2=7
Radius is 7in"
Circumference of circle formula: 2pi(radius)
2pi(7)= 43.98in of wire required so it can wrap around lamp exactly once.
Answer:
2x^2+4x-16
Step-by-step explanation:
The quadratic can be written as
f(x) = a(x-z1)(x-z2) where z1 and z2 are the roots
f(x) = a (x-2)(x- -4)
a is the leading coefficient
f(x) = 2(x-2)(x+4)
= 2(x^2 -2x+4x-8)
= 2(x^2 +2x-8)
= 2x^2 +4x-16
Answer:
<h3>#1</h3>
<u>The system of equations:</u>
- 2x + 7y = -11
- 3x + 5y = -22
Solve by elimination.
<u>Triple the first equation, double the second one, subtract the second from the first and solve for y:</u>
- 3(2x + 7y) - 2(3x + 5y) = 3(-11) - 2(-22)
- 6x + 21y - 6x - 10y = -33 + 44
- 11y = 11
- y = 1
<u>Find x:</u>
- 2x + 7*1 = -11
- 2x = -11 - 7
- 2x = -18
- x = -9
<u>The solution is:</u>
<h3>#2</h3>
<u>Simplifying in steps:</u>
- 8u - 29 > -3(3 - 4u)
- 8u - 29 > - 9 + 12u
- 12u - 8u < -29 + 9
- 4u < -20
- u < -5
