Question

A 41.0 kg child is riding a playground merry-go-round that is rotating at 60.0 rev/min. What centripetal force (in N) is exerted if he is 1.25 m from its center? (Enter the magnitude.)a-wood-floor-with-coefficient-of-static-friction-0/

Answer 1

Answer:505.94 N

Explanation:

Given

mass of child (m)=41 kg

N=60 rpm

$\omega =\frac{2\pi N}{60}=4\pi rad/s$

Radius(r)=1.25 m

and centripetal acceleration is given by $m\omega ^2r$

$F_c=41\times (4\pi )^2\times 1.25=505.94 N$