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Artyom0805 [142]
4 years ago
12

A boat displaces a volume V of water as it floats on a fresh-water lake. When the boat moves into the ocean, what volume of salt

water will it displace? (The density of fresh water is 1.0 kg/L, and the density of salt water is 1.02 kg/L)
a) 1.02 V
b) 0.98 V
c) V (the same volume)
d) 1.04 V
Physics
1 answer:
Mamont248 [21]4 years ago
7 0

Answer:

Option (b)

Explanation:

let the weight of boat is W.  In equilibrium condition, the weight of boat is equal to the buoyant force acting on the boat.

The buoyant force acting on the boat is equal to the weight of water displaced by the boat.

In case of fresh water:

Weight of the boat = weight of fresh water displaced by the boat

W = Volume of fresh water displaced x density of fresh water x g

W = V x 1 x g

W = V x g ....... (1)

In case of salt water:

Let the volume of salt water displaced is V'.

Weight of the boat = weight of salt water displaced by the boat

W = Volume of salt water displaced x density of salt water x g

W = V' x 1.02 x g    ..... (2)

Equate equation (1) and equation (2), we get

V x g = V' x 1.02 x g

V' = 0.98 V

Thus, option (b) is true.

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what volume of alcohol will have the same mass as 4.2m^3 of petrol? (density of alcohol 0.4kg/m^3 and petrol is 0.3kg/m^3)​
Alexxx [7]

Answer:

3.15m³

Explanation:

To solve this problem, let us first find the mass of the petrol from the given dimension.

       Mass  = density x volume

Volume of petrol  = 4.2m³

Density of petrol  = 0.3kgm⁻³  

       Mass of petrol  = 4.2 x 0.3  = 1.26kg

So;

      We can now find the volume of the alcohol

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7 0
3 years ago
a railroad tie weights 920 N and is 2.6 m long. How much force is required to: pick it up off the ground? lift one end and rotat
lukranit [14]

1) The minimum force needed is 920 N

2) The minimum force is 460 N

3) The minimum force is 598 N

Explanation:

1)

We can answer this part by simply looking at the forces involved. In fact, there are two forces acting on the railroad:

  • Its weight, W, acting downward
  • The force applied to lift it, F, upward

So the net force on the railroad is

\sum F = F - W

where

W = 920 N is the weight of the railroad

In order to lift the railroad, the net force must be upward, so

\sum F \geq 0

And therefore

F\geq W

which means that the minimum force needed is equal to the weight of the railroad, 920 N.

2)

In this case, we have to use the principle of equilibrium of moments.

In fact, when the railroad rotates uniformly (=constant angular speed) about its end, it means that the moment produced by the weight (acting in one direction) is equal to the moment produced by the force applied (acting in the other direction). Therefore, we can write:

W \frac{L}{2} = F L

where

W = 920 N is the weight

L = 2.6 m is the length of the railroad

F is the force applied

We wrote L/2 on the left of the equation because the weight acts at the center of mass of the railroad (located at the midpoint), while on the right it is L because the force F is applied at the end of the railroad.

Solving for F,

F=\frac{W}{2}=\frac{920}{2}=460 N

3)

This problem is similar to the previous part, however in this case, the force applied F is applied 0.6 m from the end, pivoting around the opposite end.

This means that the distance between the point of application of the force F and the pivot is

L' = L - 0.6

where

L = 2.6 m

Therefore the equation for the equilibrium of moments becomes

W\frac{L}{2}=F(L-0.6)

and substituting

W = 920 N

L = 2.6

We find the magnitude of F:

W\frac{2.6}{2}=F(2.6-0.6)\\1.3W = 2F\\F=\frac{1.3}{2}W=\frac{1.3}{2}(920)=598 N

Learn more about forces:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

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Answer:

Option C

Explanation:

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now we know the centripetal acceleration is 9 and the radius is 16 so we plug these values into our formula,

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we know the centripetal acceleration is 9 and the radius is 16 so plug these values into the formula,

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8 0
3 years ago
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