Λ= V/f
<span>but change it to represent the speed of light, c </span>
<span>λ= c/f </span>
<span>c = 3.00 x 10^8 m/s </span>
<span>Plug in your given info and solve for λ(wavelength) </span>
<span>λ= 3.00 x 10^8 m/s / 7.5 x 10^14 Hz
(3.00 x 10^8) / (7.5 x 10^14) = 300,000,000 / 750,000,000,000,000 = 0.0000004
Hope this helps :)
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Answer: a. Mass per unit length =0.0245kg/m
b. Tension =2.45x10^-8N
C. Tension = 2.45 x10^-8N
Fundamental frequency =200Hz
Explanation:
A proton in a particle accelerator is traveling at a speed of 0.99c has a speed magnitude of 2.97 x 10⁸ m/s.
<h3>What is speed of proton?</h3>
The speed of a proton is the rate at which a proton is moving through a given space.
The given speed of the proton is 0.99c
where;
<h3>What is speed of light?</h3>
The speed of light in vacuum, commonly denoted c, is a universal physical constant that is important in many areas of physics.
The value of speed of light in a vacuum is given as 3 x 10⁸ m/s.
The speed of the proton is calculated as follows;
v = 0.99 x 3 x 10⁸ m/s.
v = 2.97 x 10⁸ m/s.
Thus, a proton in a particle accelerator is traveling at a speed of 0.99c has a speed magnitude of 2.97 x 10⁸ m/s.
Learn more about speed of proton here: brainly.com/question/14663642
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(1) Doubling of the current through the wire will result in doubling of its magnetic field.
The magnetic field around a wire is a function of the current I and radial distance r

(with mu denoting the magnetic permeability of the medium). So, B is directly proportional to I. The field magnitude will double with the doubled current from 5A to 10A
(2) Using the same formula as in (1), we can see that the magnetic field is inversely proportional to the radial distance from the wire. So, a particle at 20cm will experience half the magnitude compared to a particle at 10cm.
(3) Answer
If a particle with a charge q moves through a magnetic field B with velocity v, it will be acted on by the magnetic force

So, a particle with charge -2uC will experience a magnetic force of same magnitude but opposite direction (and perpendicular to B) as compared to a particle with a charge of 2uC
<span>Ocean tides are highest when the sun, Earth, and the moon
are nearly in a line. That means at the times of New Moon
and Full Moon.</span>