An equation __has one solution. A: always B:sometimes C: never Answer : B
1 answer:
You might be interested in
Answer:
0 ; 2/9 ; 1
Step-by-step explanation:
In a roll of two dice ;
The sample space = (Number of faces on die)^number of dice rolled = 6^2 = 36
The total possible outcome = sample space = 36
The probability of an event (A) :
P(A) = number of required outcome / number of total possible outcomes
find the probability for total: a) 1,
P(total of 1)
Number of 1 total = 0
Hence, P(total of 1) = 0
b) 4 or 6;
Number of 4 total = 3
Number of 6 total = 5
3 /36 + 5 / 36 = 8/36 = 2/9
c) <13
P(total < 13)
Number of total < 13 = 36
36 / 36 = 1
ANSWER
EXPLANATION
Let the number who plays both games be
Then those who play only basketball
and those who play only baseball
We were given that 10 students play neither sports.
We can then write the following equation,
This implies that,
This simplifies to,
This gives us,
Therefore the number of students play both basketball and baseball is 2.
The probability that a student chosen from the class plays both basketball and baseball ball
EXPLANATION
Let the number who plays both games be
Then those who play only basketball
and those who play only baseball
We were given that 10 students play neither sports.
We can then write the following equation,
This implies that,
This simplifies to,
This gives us,
Therefore the number of students play both basketball and baseball is 2.
The probability that a student chosen from the class plays both basketball and baseball ball