An equation __has one solution. A: always B:sometimes C: never Answer : B

325 people were in a tour group.Six buses were completely filled and 7 people choose to walk.How many people did the bus hold

Zolol [24]

(325 - 7)÷ 6= 53
.....

4 0

3 years ago

Find the volume of the composite figure. Round your answer to the nearest hundredth

pishuonlain [190]

Answer:

The volume of the figure is 590.71 mm³

Step-by-step explanation:

To solve this problem we have to find the volume of the cylinder and the volume of the rectangular prism and add them

To calculate the volume of a cylinder we have to use the following formula:

v = volume

h = height = 3.65mm

π = 3.14

r = radius = 3.2mm

v = (π * r²) * h

we replace the unknowns with the values we know

v = (3.14 * (3.2mm)²) * 3.65mm

v = (3.14 * 10.24mm²) * 3.65mm

v = 32.1536² * 3.65mm

v = 117.36mm³

To calculate the volume of a rectangular prism we have to use the following formula:

v = volume

w = width = 14.23mm

l = length = 10.08mm

h = height = 3.3mm

v = w * h * l

we replace the values that we know

v = 14.23mm * 10.08mm * 3.3mm

v = 473.347mm³

we add the volumes

v = 117.36mm³ + 473.347mm³

v = 590.707

round to the neares hundredth

v = 590.707 mm³ = 590.71 mm³

The volume of the figure is 590.71 mm³

3 0

3 years ago

Given that z is a standard normal random variable, find z for each situation. The area between 0 and z is .4750. Answer The area

algol13

Answer:

$P(0$

And solving for z we have

$P(Z$

And we can find the value for z with the following excel code:

"=NORM.INV(0.975,0,1)"

And we got z =1.96

$P(Z>z)= 0.1314$

And we can use the complement rule and we got:

$P(Z>z) = 1-P(Z$

$P(Z$

And we can find the value for z with the following excel code:

"=NORM.INV(0.8686,0,1)"

And we got z =1.120

$P(Z$

And we can find the value for z with the following excel code:

"=NORM.INV(0.67,0,1)"

And we got z =0.440

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

We want this probability:

$P(0$

And solving for z we have

$P(Z$

And we can find the value for z with the following excel code:

"=NORM.INV(0.975,0,1)"

And we got z =1.96

For the next part we want to calculate:

$P(Z>z)= 0.1314$

And we can use the complement rule and we got:

$P(Z>z) = 1-P(Z$

$P(Z$

And we can find the value for z with the following excel code:

"=NORM.INV(0.8686,0,1)"

And we got z =1.120

For the next part we want to calculate:

$P(Z$

And we can find the value for z with the following excel code:

"=NORM.INV(0.67,0,1)"

And we got z =0.440

6 0

3 years ago

give an example of a convergent infinite series whose sum equal 3/5. explain how you know your series converges and write out wo

krek1111 [17]

Answer:

The series 1/5, 2/15, 4/45, 8/135... converges and sums up to 3/5

Step-by-step explanation:

Consider the infinite geometric series

1/5, 2/15, 4/45, 8/135...

With first term, a=1/5

common ratio, r = ⅔

The series converge because the common ratio, |r|<1.

The sum to infinity of a geometric series, S= a/(1-r)

S= 1/5 ÷ (1-⅔) = 1/5 ÷ 1/3 = 3/5

Therefore, the geometric series 1/5, 2/15, 4/45, 8/135... sums up to 3/5.

5 0

3 years ago

jamal calculated that it costs $0.43 per mile and $4.00 per day to operate his car. if jamal drive m miles over d days , which e

DaniilM [7]

Answer:

c = 4(d) + .43(m)

Step-by-step explanation:

We can test this by plugging in numbers for each of the variables. Let's say Jamal drove 5 miles over 2 days.

c = 4(2) + .43(5)

c = 8 + 2.15

c = $10.15

Have a nice day!

4 0

3 years ago