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oksano4ka [1.4K]
3 years ago
6

1-5x + 3y 452x+3y = 24​

Mathematics
1 answer:
Norma-Jean [14]3 years ago
3 0

Answer:

The answer is 1-5x+135y

Step-by-step explanation: multiply the numbers 3 and 45 which give you 135

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Which set of ordered pairs could NOT represent a function?
Kisachek [45]
C does not represents a function
4 0
2 years ago
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What is the scientific notation for a length of 0.0000923 centimeter
nataly862011 [7]

Answer:

9.23*10 to the power 5

Step-by-step explanation:

to move the point 5steps backwards

4 0
3 years ago
10 points!!! please help :(
daser333 [38]
To complete the identity, we need these fundamental identities:

1)\displaystyle{sec(x)=\frac{1}{cos(x)}

2) cos(x-y)=cos(x)cos(y)+sin(x)sin(y)

\displaystyle{csc(x)= \frac{1}{sin(x)}


Thus, by identity 1 we have:

\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}

by identity :

\displaystyle{cos(\frac{ \pi }{2}-\theta)=cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)

recall the values :

\displaystyle{ sin(\frac{ \pi }{2})^R=sin(90^o)=1\\\\

\displaystyle{ cos(\frac{ \pi }{2})^R=cos(90^o)=0, 


so: 

cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)=0+sin(\theta)=sin(\theta)


Putting all these together, we have:


\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}= \frac{1}{cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)}= \frac{1}{sin(\theta)}}

which is equal to csc(\theta), by identity 3


Answer: D
7 0
3 years ago
Find the domain and range for the function graphed below ​
Nana76 [90]

Answer:

Domain: 3, 2, 1, 0, -1 , -2 , -3

Range: 5 , 4 , 3 , 2 , 1 , 0 , -1 , -2

Step-by-step explanation:

The domain values are all of the x-values, and the range value are all of the y-values. Domain ad range can also be know as input and output.

3 0
3 years ago
Enzo and Beatriz are playing games at their local arcade. Incredibly, Enzo wins 55 tickets from every game, and Beatriz wins 111
madam [21]

Answer:

101

Step-by-step explanation:

Note that

  • 55=5\cdot 11;
  • 1111=11\cdot 101.

Here these two numbers have the common divisor 11. Find the least common multuply:

LCM(55,1111)=11\cdot 5\cdot 101=5555.

This means that  the minimum number of games that Enzo could have played will be

\dfrac{5555}{55}=101.

8 0
2 years ago
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