Answer:
2
Step-by-step explanation:
Corresponding sides are proportional in these similar triangles.
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short side/long side = k/4 = 4/8
k = 4(4/8) . . . . multiply by 4
k = 2
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<em>Additional comment</em>
The lengths of the hypotenuses can be found the same way, or using the Pythagorean theorem. Using side ratios, we have ...
l² = k(k+8) = 2(10) = 20 . . . . from MN/MO = ML/MN
l = 2√5
m² = 8(8+2) = 80 . . . . from LN/LO = LM/LN
m = 4√5
The similarity statements are ...
ΔLMN ~ ΔLNO ~ ΔNMO
The solution set is basically when are they equal. to figure this out we must set them equal. So so we will move some stuff around
x+y=5
y=5-x
y=x^2-25
we know that when they are equal their x and y values are equal. So so we know that their y values are the same so we can say:
y=y
this does not direarly help but looking above we know what both of the y's equal. so:
5-x = x^2-25
we want to set this equal to zero
0 = x^2 +x - 30
now we factor
0 = (x + 6) * (x - 5)
the only way to multiply 2 things together and get zero is for one of those things to equal 0. So so we know that to be zero one of the answers in parenthesis has to equal 0. so:
0 = (x + 6 =0) * (x - 5=0)
So now we solve for both parenthesis
x+6=0
x=-6
x-5=0
x=5
x=-6,5
10^7 is the correct answer
<span>Drake can meet his $750 planned savings goal with either concept. After 4 weeks, he was $30 less than where he planned to be ($450 instead of $480). If he simply added $250 after two more weeks, he would be at $720 instead of $750, and would have to wait one more week to take the class. Conversely, if he added $15 to the next two weeks' savings, he would recoup the $30 he pulled out of the savings in those two weeks and would be back on the path to being able to take the course at the end of the 6-week period as originally planned.</span>
