4(-3x – 5) = 2(-6x + 8)

05) A polynomial function f of degree(6) whose coefficients are real numbers has the zeros i, 4-i,2+i . Find the remaining zeros

arlik [135]

The degree of the polynomial function f is the number of zeros function f has.

The remaining zeros of the polynomial function are -i, 4 + i and 2 - i

<h3>How to determine the remaining zeros</h3>

The degrees of the polynomial is given as;

Degree = 6

The zeros are given as:

i, 4-i,2+i

The above numbers are complex numbers.

This means that, their conjugates are also zeros of the polynomial

Their conjugates are -i, 4 + i and 2 - i

Hence, the remaining zeros of the polynomial function are -i, 4 + i and 2 - i

Read more about polynomials at:

brainly.com/question/4142886

3 0

2 years ago

If the mean time between unscheduled maintenance of LCD displays in a hospital’s CT scan facility is 4000 hours, what is the pro

musickatia [10]

Likely

6000 hours is over the mean average, but it is not impossible that it will not happen.

6 0

3 years ago

The distance a race car travels is given by the equation d=v0t+12at2 where v0 is the initial speed of the race car, a is the acc

Scrat [10]

Answer:

v0 + 1/2at

Step-by-step explanation: Given that the distance a race car travels is given by the equation d = v0t+12at2 where v0 is the initial speed of the race car, a is the acceleration, and t is the time travelled.

The equation for the driver's average speed s during the acceleration will be:

(v0t+12at2) / t

Since Average speed is equal to distance divided by time.

Therefore, the equation will be:

v0+1/2at

7 0

3 years ago

Historically, the proportion of people who trade in their old car to a car dealer when purchasing a new car is 48%. Over the pre

choli [55]

Answer:

$z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717$

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.

Step-by-step explanation:

Data given and notation

n=115 represent the random sample taken

X=46 represent the number of people that have traded in their old car.

$\hat p=\frac{46}{115}=0.4$ estimated proportion of people that have traded in their old car

$p_o=0.48$ is the value that we want to test

$\alpha=0.1$ represent the significance level

Confidence=90% or 0.9

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.48.:

Null hypothesis: $p\geq 0.48$

Alternative hypothesis: $p < 0.48$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.1$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.

4 0

3 years ago

Mr. Chang’s class has 28 students, 4/7 of whom are girls. Which equation shows how to determine the number of girls in Mr. Chang

mars1129 [50]

Answer:

b

Step-by-step explanation:

6 0

3 years ago

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