Answer:
imaginary because i see no line.
Explanation:
The answer for the above question is the control. A control is that particular test that is done under standard conditions. Therefore, a controlled experiment is an experiment is where one test is done under standard or normal conditions, and all the other tests compare to the standard conditions. The standard conditions are majorly a temperature of 273 K or 0 degrees Celsius, and a pressure of 1 atm or 760 mmHg.
<span>11.3 kPa
The ideal gas law is
PV = nRT
where
P = Pressure
V = Volume
n = number of moles
R = Ideal gas constant (8.3144598 L*kPa/(K*mol) )
T = Absolute temperature
We have everything except moles and volume. But we can calculate moles by starting with the atomic weight of argon and neon.
Atomic weight argon = 39.948
Atomic weight neon = 20.1797
Moles Ar = 1.00 g / 39.948 g/mol = 0.025032542 mol
Moles Ne = 0.500 g / 20.1797 g/mol = 0.024777375 mol
Total moles gas particles = 0.025032542 mol + 0.024777375 mol = 0.049809918 mol
Now take the ideal gas equation and solve for P, then substitute known values and solve.
PV = nRT
P = nRT/V
P = 0.049809918 mol * 8.3144598 L*kPa/(K*mol) * 275 K/5.00 L
P = 113.8892033 L*kPa / 5.00 L
P = 22.77784066 kPa
Now let's determine the percent of pressure provided by neon by calculating the percentage of neon atoms. Divide the number of moles of neon by the total number of moles.
0.024777375 mol / 0.049809918 mol = 0.497438592
Now multiply by the pressure
0.497438592 * 22.77784066 kPa = 11.33057699 kPa
Round the result to 3 significant figures, giving 11.3 kPa</span>
I think it's B.) Alcohols
Answer:
has higher boiling point
Explanation:
has higher boiling point because in
,
has a very strong dipole and we know that whenever there is dipole-dipole interaction then boiling point increases. On the other hand in
the NO group has not so strong dipole which weakens its boiling point
So the boiling point of
is higher than the boiling point of