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S_A_V [24]
4 years ago
11

What is the IUPAC name for the following compound?

Chemistry
1 answer:
nikklg [1K]4 years ago
5 0

Answer:

c. 5-chloro-3-methyl-2-hexanone

Explanation:

The IUPAC nomenclature of alkanes are given as follows:

  • Select the longest possible carbon chain.
  • For the number of carbon atom, we add prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.
  • A suffix '-ane' is added at the end of the name.
  • If two of more similar alkyl groups are present, then the words 'di', 'tri' 'tetra' and so on are used to specify the number of times these alkyl groups appear in the chain.

For any substituent attached, the numbering is done according to the priority of the functional group which is:-

Carboxylic Acids  > Acid Anhydrides   >  Esters    > Acyl Halides   > Amides   > Nitriles   >  Aldehydes    > Ketones   > Alcohols   > Thiols   > Amines   > Ethers   >  Sulphides   > Alkenes   > Alkynes   > Alkyl Halides   > Nitro   > Alkanes

Thus,

Numbering is shown below. The long chain is 6 membered ring having substituents ketone at C-2, methyl group at C-3 and chloro bond at C-5

The name is:-

<u>c. 5-chloro-3-methyl-2-hexanone</u>

 

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CH_3NO_2 has higher boiling point because in CH_3NO_2 , NO_2  has a very strong dipole and we know that whenever there is dipole-dipole interaction then boiling point increases. On the other hand in CH_3-O-NO the NO group has not so strong dipole which weakens its boiling point

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