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Harrizon [31]
3 years ago
5

How many atoms are there in 5.7 mol of hafnium?

Chemistry
2 answers:
Mashutka [201]3 years ago
7 0
<span>In 5.70 mol of Hafnium there are 34,326 208 203*10^23 atoms.</span>
Doss [256]3 years ago
4 0

Answer:There are 3.43\times 10^{24} atoms in 5.7 mol of hafnium.

Explanation:

Moles of hafnium = 5,7 moles

1 mol = N_A=6.022\times 10^{23} atoms

Number of atoms in 5.7 moles of hafnium :

=5.7\times 6.022\times 10^{23} atoms=3.43\times 10^{24} atoms

There are 3.43\times 10^{24} atoms in 5.7 mol of hafnium.

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Determine the empirical formula of the following compound if a sample contains 0.104 molK, 0.052 molC, and 0.156 molO;?
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Explanation:

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Method

From the given parameters, to calculate the empirical formula of the elements K, C and O, we reduce the given moles to the simplest fraction.

Empirical formula is the simplest formula of a compound and it differs from the molecular formula which is the actual formula of a compound.

  • Divide the given moles through by the smallest which is C, 0.052mol.
  • Then approximate values obtained to the nearest whole number of multiply by a factor to give a whole number ratio.
  • This is the empirical formula

Solution

Elements                             K                       C                    O

Number of moles            0.104                0.052            0.156

Dividing by the

smallest                       0.104/0.052     0.052/0.052  0.156/0.052

                                            2                           1                     3

The empirical formula is K₂CO₃      

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