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Basile [38]
3 years ago
6

2x + 3y = 5x - y Complete the missing value in the solution to the equation. ( ,0)

Mathematics
2 answers:
AnnZ [28]3 years ago
7 0

Answer:

0

Step-by-step explanation:

If you replace y with 0 (which you do since you are given y = 0 and you are trying to find x from the (_,0) point), you get 2x = 5x. The only way for x to satisfy this is x = 0.

Licemer1 [7]3 years ago
4 0
Can u help answer my question thx
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Evaluate c (y + 7 sin(x)) dx + (z2 + 9 cos(y)) dy + x3 dz where c is the curve r(t) = sin(t), cos(t), sin(2t) , 0 ≤ t ≤ 2π. (hin
saw5 [17]
Treat \mathcal C as the boundary of the region \mathcal S, where \mathcal S is the part of the surface z=2xy bounded by \mathcal C. We write

\displaystyle\int_{\mathcal C}(y+7\sin x)\,\mathrm dx+(z^2+9\cos y)\,\mathrm dy+x^3\,\mathrm dz=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r

with \mathbf f=(y+7\sin x,z^2+9\cos y,x^3).

By Stoke's theorem, the line integral is equivalent to the surface integral over \mathcal S of the curl of \mathbf f. We have


\nabla\times\mathbf f=(-2z,-3x^2,-1)

so the line integral is equivalent to

\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\mathrm d\mathbf S
=\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv


where \mathbf s(u,v) is a vector-valued function that parameterizes \mathcal S. In this case, we can take

\mathbf s(u,v)=(u\cos v,u\sin v,2u^2\cos v\sin v)=(u\cos v,u\sin v,u^2\sin2v)

with 0\le u\le1 and 0\le v\le2\pi. Then

\mathrm d\mathbf S=\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv=(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv

and the integral becomes

\displaystyle\iint_{\mathcal S}(-2u^2\sin2v,-3u^2\cos^2v,-1)\cdot(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv
=\displaystyle\int_{v=0}^{v=2\pi}\int_{u=0}^{u=1}u-6u^4\sin^3v-4u^4\cos v\sin2v\,\mathrm du\,\mathrm dv=\pi<span />
4 0
2 years ago
What is the scale factor use to create this dilation?
andrezito [222]
Given Info: "The dashed triangle is the image of the solid triangle"

So the "before" is the large solid triangle and the "after" is the smaller dashed triangle.

The horizontal side of the solid triangle is 15 units. The corresponding side for the dashed triangle is 3 units. Dividing the two values gives: 3/15 = 1/5 = 0.2

Make this value negative. The reason why is due to the fact that we have a sort of reflection going on as we're scaling down the figure. 

So the final answer is  -0.2

3 0
3 years ago
Please explain the how you got the answers thanks asap
stich3 [128]

Answer:

a) 90 stamps

b) 108 stamps

c) 333 stamps

Step-by-step explanation:

Whenever you have ratios, just treat them like you would a fraction! For example, a ratio of 1:2 can also look like 1/2!

In this context, you have a ratio of 1:1.5 that represents the ratio of Canadian stamps to stamps from the rest of the world. You can set up two fractions and set them equal to each other in order to solve for the unknown number of Canadian stamps. 1/1.5 is representative of Canada/rest of world. So is x/135, because you are solving for the actual number of Canadian stamps and you already know how many stamps you have from the rest of the world. Set 1/1.5 equal to x/135, and solve for x by cross multiplying. You'll end up with 90.

Solve using the same method for the US! This will look like 1.2/1.5 = x/135. Solve for x, and get 108!

Now, simply add all your stamps together: 90 + 108 + 135. This gets you a total of 333 stamps!

5 0
3 years ago
g In the sample of 134 South Korean tourists, 57 of them were satisfied with their Jeju experience. In the sample of 150 other c
nasty-shy [4]

Answer:

The test statistic = -0.93

Step-by-step explanation:

The test statistic is given by the formula

z = (X₁ - X₂) ÷ √(σₓ₁² + σₓ₂²)

where X₁ = proportion of data of South Korean tourists = (57/134) = 0.425

X₂ = proportion of other country tourists = (72/150) = 0.48

σₓ₁ = standard error in data 1 = √[p(1-p)/n]

= √(0.425 × 0.575/134) = 0.0427

σₓ₂ = standard error in data 2 = √[p(1-p)/n]

= √(0.48 × 0.52/150) = 0.0408

z = (X₁ - X₂) ÷ √(σₓ₁² + σₓ₂²)

z = (0.425 - 0.48) ÷ √(0.0427² + 0.0408²)

z = -0.055 ÷ 0.0590586996

z = -0.9313

Hope this Helps!!!

6 0
3 years ago
A car is 160 inches lorrg.
Andreyy89
The truck is 171.2%. if you calculate the percentage of 160 and add them together, you will get 171.2
7 0
2 years ago
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