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Alex_Xolod [135]
3 years ago
12

If a much heavier stone rolled off the same cliff would it hit the ground more quickly

Physics
1 answer:
qaws [65]3 years ago
5 0
Heavier objects do not fall faster than lighter objects when they are dropped from a certain height IF there is no resistance from the air. So, if you were in a vacuum, the two things would fall at the same rate.
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Bond [772]

Answer:C

Explanation:

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15. Muous produced by snails help them move along the ground How does the mucus help maits
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15.C Mucus reduces friction

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A jet plane flying 600 m/s experiences an acceleration of 4g when pulling out of the dive. What is the radius of curvature of th
Gnoma [55]

Answer:

91.84 m/s²

Explanation:

velocity, v = 600 m/s

acceleration, a = 4 g = 4 x 9.8 = 39.2 m/s^2

Let the radius of the loop is r.

he experiences a centripetal force.

centripetal acceleration,

a = v² / r

39.2 x r = 600 x 600

r = 3600 / 39.2

r = 91.84 m/s²

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8 0
3 years ago
A current is flowing in a wire in direction 3i + 4j where the direction of the magnetic field is 5j + 12k. The force on the wire
nasty-shy [4]

Answer:

F = 0.768 i ^ - 0.576 j ^ + 0.24 k ^

the correct answer is "b"

Explanation:

The magnetic force is

          F = i l x B

The bold are vectors, in this case they give us the direction of the current and the magnetic field, for which we can solve as a determinant

         

F = i \left[\begin{array}{ccc}x&y&z\\3&4&0\\0&5&12\end{array}\right]

resolver

     F = i ^ (4 12 - 0) + j ^ (0- 3 12) + k ^ (3  5 - 0)

     F = i (48 i ^ - 36 j ^ + 15 k⁾

in this case i is the value of the current flowing through the cable

     i = 16 mA = 0.016 A

     F = 0.768 i ^ - 0.576 j ^ + 0.24 k ^

When reviewing the different answers, the correct answer is "b"

6 0
3 years ago
How much heat energy must be added to 52kg Of water at 68°F to raise the temperature to 212°F? The specific heat capacity for wa
Anna [14]

Answer:

The amount of energy added to rise the temperature Q = 17413.76 KJ

Explanation:

Mass of water = 52 kg

Initial temperature T_{1} = 68 °F = 20° c

Final temperature T_{2} = 212 °F = 100° c

Specific heat of water  C = 4.186 \frac{KJ}{kg c}

Now heat transfer Q = m × C × ( T_{2}  - T_{1} )

⇒ Q = 52 × 4.186 × ( 100 - 20 )

⇒ Q = 17413.76 KJ

This is the amount of energy added to rise the temperature.

4 0
3 years ago
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