Three origin, the identical second point to the charges right of atx 2.0 hc 50 cm, are and placed the on thrd the 1s at x-axis.
1 answer:
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Answers:
No, They will attract each other, B, and neither direction
Explanation:
Since the two already presented particles in the diagram represent both opposing charges due to the direction of the arrows (the arrows facing away from the particle shows a positive charge and the particles facing towards the particle show a negative charge), not only because of this but as the arrows between the particles show an attracting magnetic field, then it can be concluded that the particles will attract to each other and if another particle was introduced into the diagram of a positive charge, then it would attract to the negatively charged particle. If you have any questions or need further explanation, please comment below. E2021, have a great day.
A) The position at t = 2.0 sec is 43.0 m east
B) The position is 55 m east
Explanation:
A)
In order to solve the problem, we take the east direction as positive direction.
We know that:
- at t = 0, the motorcyclist is at a position of
- at t = 0, the initial velocity of the motorcyclist is east
- The acceleration of the motorcyclist is constant and it is
Since the motion is a uniformly accelerated motion, the position of the motorcylist is given by the expression
where t is the time.
Substituting t = 2.0 s, we find the position:
B)
The velocity of the motoryclist can be found by calculating the derivative of the position. Therefore, it is:
where:
is the initial velocity
is the acceleration
We want to find the time t at which the velocity is
v = 25 m/s
Solving the equation for t,
And therefore, the position at t = 2.5 s is:
Learn more about accelerated motion:
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