Question

If 2x^2+5x-12=(2x-3)(x+4), which equation(s) should be solved to find the roots of 2x^2+5x-12=0

Answer 1

Answer:

see explanation

Step-by-step explanation:

Given 2x² + 5x - 12 in factored form, then to find the roots equate to zero, that is

(2x- 3)(x + 4) = 0

Equate each factor to zero and solve for x

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = $\frac{3}{2}$

x + 4 = 0 ⇒ x = - 4

Roots are x = - 4 and x = $\frac{3}{2}$

Answer 2

Answer:

The equation (2x-3)(x+4)=0 should be solved to find the roots of 2x²+5x-12=0.

Step-by-step explanation:

The given equation is

$2x^2+5x-12=(2x-3)(x+4)$              .... (1)

We need to find an equation that should be solved to find the roots of the equation

$2x^2+5x-12=0$

To find the roots of the equation we need to write the equation in factor form.

From equation (1) it is clear that the factor form of 2x²+5x-12 is (2x-3)(x+4). So using (1), we get

$(2x-3)(x+4)=0$

Using zero product property, we get

$(2x-3)=0\Rightarrow x=\frac{3}{2}$

$(x+4)=0\Rightarrow x=-4$

Therefore the equation (2x-3)(x+4)=0 should be solved to find the roots of 2x²+5x-12=0.