The data given on the table about the ten participants in the health study shows that B. The post-run mean and median are the same value.
<h3>What is the post run mean?</h3>
This can be found as:
= (87 + 95 + 96 + 101 + 110 + 104 + 100 + 101 + 90 + 96) / 10
= 98
<h3>What is the post run median?</h3>
First order the pulses from smallest to largest:
= 87, 90, 95, 96, 96, 100, 101, 101, 104, 110
The two digits in the middle are:
96 and 100
The median will be:
= (96 + 100) / 10
= 98
In conclusion, option B is correct.
Find out more on the median at brainly.com/question/396397.
Answer:
74
Step-by-step explanation:
To receive an award, student must obtain a score at or above the upper quartile, from.tye boxplot, the upper quartile is depicted by the endpoint of the box. Hence, the upper quartile of the distribution is 74. Hence only stude Ts who score 74 and above will receive an award Hence, the minimum score required is 74.
Hey there!
(6^3 * 2^6) / 2^3
= (6 * 6 * 6 * 2 * 2 * 2 * 2 * 2 * 2) / 2 * 2 * 2
= (36 * 6 * 4 * 4 * 4) / 4 * 2
= (216 * 16 * 4) / 8
= 3,456 * 4 / 8
= 13,824 / 8
= 1,728
Looking for something that gives you the result of: 1,728
Option A.
12^3
= 12 * 12 * 12
= 144 * 12
= 1,728
Option A. is. possible answer
Option B.
6^3
= 6 * 6 * 6
= 36 * 6
= 216
216 ≠ 1,728
Option B. is incorrect
Option C.
12^6
= 12 * 12 * 12 * 12 * 12 * 12
= 144 * 144 * 144
= 20,736 * 144
= 2,985,984
2,985,984 ≠ 1,728
Option C. is also incorrect
Option D.
2^6 * 2^3
= 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2
= 4 * 4 * 4 * 4 * 2
= 16 * 16 * 2
= 256 * 2
= 512
512 ≠ 1,728
Option D. is also incorrect
Option E.
2^3 * 3^3
= 2 * 2 * 2 * 3 * 3 * 3
= 4 * 2 * 9 * 3
= 8 * 27
= 216
216 ≠ 1,728
Option E. is also incorrect.
Therefore, the answer should be:
Option A. 12^3
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
