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garik1379 [7]
3 years ago
12

WORTH 10 points. Explain work

Mathematics
1 answer:
Soloha48 [4]3 years ago
6 0
This should help you. Use the Pythagorean theorem and you will find the length of the hypotenuse of a right triangle here

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Kevin invest $2,000 at 4.6% compounded continuously. How long will it take him to have $3,700
natali 33 [55]

Answer:

t=In(37/20)/0.046

Step-by-step explanation:

p=2000

r=0.046

A=3700

t=?

3700=2000e^0.046t

switch sides

2000e^0.046t=3700

Divide both sides by 2000

$2000e^0.046t/2000=$3700/2000

Simplify

e^0.046=37/20

Apply exponent rules

0.046=37/20

Solve 0.046t = ln(37/20)

t=In(37/20)/0.046

6 0
2 years ago
What is the slope of a line with these coordinate points&gt;<br><br> (-5,-4) (5,1)
Tomtit [17]
Para sacar la pendiente de dos coordenada:
X1-X2/Y1-Y2
Entonces:
-5-5/-4-1=-10/-5=2 esa es la pendiente
7 0
3 years ago
Read 2 more answers
State the converse<br><br> Please helps asap
Paladinen [302]

Answer: True

Step-by-step explanation:

If x2 = 49, then x = 7. True; x = 7 if and only if x^2 = 49.

I hope this solves your problem! It was a little tricky but I tried.

please mark me Brainliest if your able

have a blessed day

7 0
3 years ago
What is the nearest whole percent of 45
kvv77 [185]

Answer:

Step-by-step explanation: 45% based on the way you state the question. 45% is a whole percent.

6 0
3 years ago
Read 2 more answers
If Vector u=(5,-7) and v=(-11,3), 2v-6u=_____ and ||2v-6u||≈_____
Sauron [17]
<h2>Answer:</h2>

2\vec{v}-6\vec{u}=(-52,48) \\ \\ ||2\vec{v}-6\vec{u}||=75.28}

<h2>Step-by-step explanation:</h2>

In this problem we have two vectors:

\vec{u}=(5,-7) \ and \ \vec{v}=(-11,3)

So we need to find two things:

2\vec{v}-6\vec{u}

and:

||2\vec{v}-6\vec{u}||

FIRST:

In this case we have the multiplication of vectors by scalars. A scalar is a simple number, so:

2\vec{v}-6\vec{u} \\ \\ Replace \ \vec{v} \ and \ \vec{u} \ by \ the \ given \ vectors: \\ \\ 2(-11,3)-6(5,-7) \\ \\ Multiply \ each \ component \ by \ the \ corresponding \ scalar:\\ \\ (2\times (-11),2\times 3)+(-6\times 5,-6\times (-7)) \\ \\ (-22,6)+(-30,42) \\ \\ Sum \ of \ vectors: \\ \\ (-22-30,6+42) \\ \\ \therefore \boxed{(-52,48)}

SECOND:

If we name:

\vec{w}=2\vec{v}-6\vec{u}

Then, ||2\vec{v}-6\vec{u}|| is the magnitude of the vector \vec{w}. Therefore:

||\vec{w}||=||2\vec{v}-6\vec{u}|| \\ \\ ||\vec{w}||=||(-52,48)|| \\ \\ ||\vec{w}||=\sqrt{(-58)^2+48^2} \\ \\ ||\vec{w}||=\sqrt{3364+2304} \\ \\ ||\vec{w}||=\sqrt{5668} \\ \\ \boxed{||\vec{w}||=75.28}

5 0
3 years ago
Read 2 more answers
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