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ziro4ka [17]
3 years ago
11

Need help solving for Y

Mathematics
1 answer:
faust18 [17]3 years ago
8 0
45 degreesssss please brainliest answer plsss.
You might be interested in
Solve the system: {4x-7y=30, 4x-5y=90
Lerok [7]

Answer:

x=60, y=30

Step-by-step explanation:

4x-7y=30

4x-5y=90

Subtract the equations

4x-7y=30-4x-5y=90

=2y=60

Solve 2y=60

Divide both sides by 2

2y/2=60/2

Simplify;

y=30

For 4x-7*30=30 for x

4x-7y*30=30

Multiply the numbers:7*30=210

4x-210=30

Add 210 to both sides

4x-210+210=30+210

Simplify;

4x=240

Divide both sides by 4

4x/4=240/4

Simplify

x=60

The solutions to the system of equations are:

x=60, y=30

Hope this helped!!!

7 0
3 years ago
Amber built a large rectangular garden that is 9 meters long and had an area of 72 square meters, what is the perimeter of amber
drek231 [11]
So we know that the length of the rectangle is 9 meters.

In order to find area of a rectangle, you multiply the length by the width.

To find the width, you divide the area by the side you do have , which is 9 meters.

72 divided by 9 is 8.

So the width 8 meters, and now to find the perimeter you must add all sides of the rectangle.

9+9+8+8 = 34.

The perimeter of the rectangular garden is 34 meters.
7 0
2 years ago
What are the coordinates of B if the midpoint of line segment AB is (2,-5) and the coordinates of point A is (4,4)?
Vlad1618 [11]

Answer:

i think it will be 20 unit diatance .

6 0
3 years ago
Simple math equation but in not very bright in the head, help would be appreciated :)
algol [13]

Answer:

AA similarity

Step-by-step explanation:

Using angle sum theorem, you can clearly find out the missing angles on the left and right triangles are 40° and 50° respectively.

Therefore, by using any two angles in the triangles, you can prove they are similar by AA similarity.

4 0
2 years ago
Let a and b be real numbers satisfying a^3 - 3ab^2 = 47 and b^3 - 3a^2 b = 52. Find a^2 + b^2.
boyakko [2]

Answer: a²+b² = -99/2

Step-by-step explanation:

Since we are given two equations, this equations will be solved simultaneously to get a² and b²

a³ - 3ab² = 47 ... 1

b³ - 3a² b = 52... 2

From 1, a(a² - 3b²) = 47...3

From 2, b(b² - 3a²) = 52... 4

Adding 3 and 4, we have;

a²+b²-3b²-3a² = 99 (note that a and b will no longer be part of the equations as they have been factored out)

a²+b²-(3b²+3a²) = 99

(a²+b²) -3(b²+a²)= 99

Taking the difference we have

- 2(a²+b²) = 99

a²+b² = -99/2

8 0
3 years ago
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