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agasfer [191]
2 years ago
14

A store owner has 7.41 lbs. of candy. If she puts the candy into 9 jars, how much candy will each jar contain with how much left

over?
Mathematics
2 answers:
BARSIC [14]2 years ago
6 0
There would be about 0.82 lbs of candy in the jar.
Explanation: 7.41 divided by 9= .82333
inna [77]2 years ago
5 0
Each jar will contain .82 lbs of candy. The left over remaining candy will be .03 lbs :)
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Trigonometry
Alla [95]

90° is equal to  \frac{\pi}{2} or 1.5707 radians.

Step-by-step explanation:

Step 1:

If an angle is represented in degrees, it will be of the form x°.  

If an angle is represented in radians, it will be of the form \frac{\pi}{x} radians.

To convert degrees to radians, we multiply the degree measure by \frac{\pi}{180}.

For the conversion of degrees to radians,

the degrees in radians = (given value in degrees)(\frac{\pi}{180}).

Step 2:

To convert 90°,

90 (\frac{\pi}{180} ) = \frac{\pi}{2}.

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So 90° is equal to \frac{\pi}{2} or 1.5707 radians.

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saveliy_v [14]

Answer:

The required probability is 0.533.

Step-by-step explanation:

Consider the provided information.

The actual weight of the chocolate has a uniform distribution ranging from 31 to 32.5 ounces.

Let x is the random variable for the actual weight of chocolate.

According to PDF function.

P(a\leq x\leq b)=\int\limits^b_a {f(x)} \, dx

Where f(x)=\left\{\begin{matrix}\frac{1}{b-a} & a

It is given that ranging from 31 to 32.5 ounces.

Substitute a=31 and b=32.5 in above function.

f(x)=\left\{\begin{matrix}\frac{1}{32.5-31} & 31

f(x)=\left\{\begin{matrix}\frac{1}{1.5} & 31

We need to find the probability that a box weighs less than 31.8 ounces

Now according to PDF:

P(x

P(x

Hence, the required probability is 0.533.

6 0
3 years ago
How many times will 1/4 go into 2 2/4
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