Answer:
3.51 g of oxygen per gram of gasoline is required.
Explanation:
Solution:
First of all we will write the balance chemical equation.
C8H18 + 12.5O2 → 8CO2 + 9H2O
This equation shows that,
1 mole of gasoline react with 12.5 mole of oxygen for complete burning.
mass of one mole of gasoline = 8×12 + 18×1 = 114 g
mass of 12.5 mole of oxygen = 12.5 (16×2) = 400 g
Formula:
mass of oxygen per gram of gasoline = (400 / 114) = 3.51
so, 3.51 g of oxygen require for per gram of gasoline.
The atom that is made up of two protons is He. The number of neutrons is also two. The number of electrons matters in the charge. So to make 10 electrons, we add 8 more. hence, 4/2 He 8-.
Answer:
I dont know at all and that is confusing.
