Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56


fts
Now using Formula for time and range as

Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,


T is approximately equals to 4 sec.
Answer:
No because the angle of point C is NOT congruent to the angle of point A.
Step-by-step explanation:
A quadrilateral MUST be a parallelogram if it has both pairs of its opposite angles congruent.
Answer:
1 + (11-4)^2 +3x5
Step-by-step explanation:
1 + (11-4)^2 +3x5
1 + (7)^2 + 3 x 5
1 + 49 + 15
50 + 15 = 65
48 = 2*2*2*2*3
84 = 2*2*3*7
Looking for common factors we get the GCF to be 2*2*3 = 12
Its B
3 24/99 is the mixed number
321/99 is the fraction