19x - 11 = 10x + 7
9x = 18
x = 2
19x - 11 = 19(2) - 11 = 27
3y + 27 = 180
3y = 153
y = 51
answer
x = 2 and y = 51
Answer:
Correct option: Type II error.
Step-by-step explanation:
In statistical hypothesis testing two kind of errors can be committed by the researcher.
- Type I error: The probability of rejecting a null hypothesis when in fact it is true.
- Type II error: The probability of not rejecting a null hypothesis when in fact it is false.
The power of the test is defined as the probability of rejecting a false null hypothesis. It is denoted by <em>β</em>.
Then the probability of Type II error can be defined as:
P (Type II error) = 1 - <em>β</em>.
The power of the test is affected by the significance level<em>.</em>
If the significance level is less than the power is also less.
The significance level is related to the <em>p</em>-value of the test.
So the P(Correct) = 1 - <em>p</em>-value.
Answer:
Janice examines the given triangle and estimates that the longest side has a length of 25 units―if it is a right triangle. How does her estimate compare to the actual length? It is under by approximately 0.6 units.
Step-by-step explanation:
Answer:
(a) 
(b) 3
(c) 27
(d)
Step-by-step explanation:
We need simplify the given expressions.
(a)
Consider the given expression is


Using the properties of exponents we get
![[\because (a^m)^n=a^{mn}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a%5Em%29%5En%3Da%5E%7Bmn%7D%5D)
![[\because a^ma^n=a^{m+n}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5Ema%5En%3Da%5E%7Bm%2Bn%7D%5D)

(b)
Consider the given expression is


Using the properties of exponents we get
![[\because (a^m)^n=a^{mn}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a%5Em%29%5En%3Da%5E%7Bmn%7D%5D)
![[\because a^ma^n=a^{m+n}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5Ema%5En%3Da%5E%7Bm%2Bn%7D%5D)


(c)
Consider the given expression is

Using the properties of exponents we get
![[\because a^{-n}=\dfrac{1}{a^n}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E%7B-n%7D%3D%5Cdfrac%7B1%7D%7Ba%5En%7D%5D)

(d)
Consider the given expression is

Using the properties of exponents we get
![[\because a^ma^n=a^{m+n}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5Ema%5En%3Da%5E%7Bm%2Bn%7D%5D)

![[\because a^{-n}=\dfrac{1}{a^n}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E%7B-n%7D%3D%5Cdfrac%7B1%7D%7Ba%5En%7D%5D)
Answer:
21
Step-by-step explanation:
This is a substitution question,we are to substitute a given value in place of a certain letter
So let's solve
2x^2-x
And since x is given to be -3
So let's substitute
2(-3)^2-(-3)
2(9)-(-3)
18+3
21
So the final answer is 21