Answer:
9x-27
Step-by-step explanation:
4(x-3)+5(x-3)=4x-12+5x-15=4x+5x-12-15=9x-27
The surface area of the rectangular prism with the dimensions that are stated is: 384 in.²
<h3>What is the Surface Area of a Triangular Prism?</h3>
Surface area = perimeter of base × height of prism + 2(base area)
= (s1 + s2 + s3)L + 2(1/2bh)
Given the following:
- side of base (s1) = 6 in.
- side of base (s2) = 8 in.
- side of base (s3) = 10 in.
- Length of prism (L) = 14 in.
- Triangular base length (b) = 6 in.
- h = 8 in.
Surface area = (6 + 8 + 10)14 + 2(1/2 × 6 × 8)
Surface area = 384 in.²
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Answer:
99
Step-by-step explanation:
99 x 33 x 3 can be simplified to 99 x 99. If you square root this you will end up with 99
Answer:
Option E is correct.
The expected number of meals expected to be served on Wednesday in week 5 = 74.2
Step-by-step Explanation:
We will use the data from the four weeks to obtain the fraction of total days that number of meals served at lunch on a Wednesday take and then subsequently check the expected number of meals served at lunch the next Wednesday.
Week
Day 1 2 3 4 | Total
Sunday 40 35 39 43 | 157
Monday 54 55 51 59 | 219
Tuesday 61 60 65 64 | 250
Wednesday 72 77 78 69 | 296
Thursday 89 80 81 79 | 329
Friday 91 90 99 95 | 375
Saturday 80 82 81 83 | 326
Total number of meals served at lunch over the 4 weeks = (157+219+250+296+329+375+326) = 1952
Total number of meals served at lunch on Wednesdays over the 4 weeks = 296
Fraction of total number of meals served at lunch over four weeks that were served on Wednesdays = (296/1952) = 0.1516393443
Total number of meals expected to be served in week 5 = 490
Number of meals expected to be served on Wednesday in week 5 = 0.1516393443 × 490 = 74.3
Checking the options,
74.3 ≈ 74.2
Hence, the expected number of meals expected to be served on Wednesday in week 5 = 74.2
Hope this Helps!!!
Answer:
4x3=12
Step-by-step explanation:
