Answer:
The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.
Step-by-step explanation:
The area of a sphere is given by the following formula:

In which A is the area, measured in cm², and r is the radius, measured in cm.
Assume that the radius r of a sphere is expanding at a rate of 40 cm/min.
This means that 
Determine the rate of change in surface area when r = 20 cm.
This is
when
. So

Applying implicit differentiation.
We have two variables, A and r, so:



The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.
Answer:
$129.02
Step-by-step explanation:
$120 multiplied by the sales tax 1.0752 = $129.024; Round .024 to the nearest tenths to get .02
Answer:
Right answer is B) x>-10 and x<10
Answer: The answer is shorter than and ll
Step-by-step explanation: