All categories

3 years ago

Help me pleaseeee (10 points )

Mathematics

2 answers:

julia-pushkina [17]3 years ago

8 0

The answer would be 14. hope this helps

krek1111 [17]3 years ago

5 0

Answer
It would be 14
Explanation
Bababoey is fhe explantion

You might be interested in

Is 4 to 7 the same as 7 to 4? Explain why or why not

Pavlova-9 [17]

Yes

Step-by-step explanation:
4×7=28
and 7×4 also equal to 28

8 0

3 years ago

The ratio of the number of people who own a cat to the number of people who own a dog is 5:7. If there are 12 more people who ow

topjm [15]

Answer:

30 people own a cat

Step-by-step explanation:

6 0

3 years ago

What is 1/8 in a decimal

sukhopar [10]

To get the answer, divide 1 by 8
Which equals 0.125
And that is your answer.

Hope I Helped You!!! :-)

Have A Good Day!!!

7 0

2 years ago

Read 2 more answers

Which value is equivalent to 48 ÷ ((2 + 6) × 2) − 1?

nalin [4]

Answer:

Step-by-step explanation:

use PEMDAS=

2+6=12

12x2=24

48/24=2

2-1= 1

6 0

3 years ago

Read 2 more answers

If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

2 years ago