Question

The quadratic equation given describes the area of the shaded region of each figure. Use the equation to find for the length and width of the figure
(s-2) (s+6) = 153​

Answer 1

Answer:

Step-by-step explanation:

To find the length and width of the figure given the equation (s-2) (s+6) = 153​, we will find the equivalent value of s by factoring.

(s-2) (s+6) = 153​

s²+6s-2s-12 = 153

s²+4s-12-153 = 0

s²+4s-165 = 0

s²+15s-11s-165 = 0

s(s+15)-11(s+15) = 0

s+15(s-11) = 0

s+15 = 0 and s-11 = 0

s = -15 and 11

s cannot be negative

Hence s = 11

The length of the figure is s

The width is s+6

Length = 11

Width = 11+6 = 17

Hence the length of the figure is 11 and the width is 17