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3 years ago

1/3m + L is greater than or equal to 8 solve the inequality for L

Mathematics

1 answer:

hodyreva [135]3 years ago

3 0

Answer:

1/3m+L>8 (TAKE 1/3M to the other side of the inequality)

L is greater than or equal to 8 - 1/3m

Step-by-step explanation:

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5) (5x2 + 4) — (5 + 5x3)

Licemer1 [7]

(5x²+4)–(5+5x³)
25x+4–5+125x
150x–1

8 0

3 years ago

Ms santos seashells into 4 row she puts 6 seashells in each row how many seachells are there altogether

kati45 [8]

4 rows and 6 seashells in each row.
Row 1: 0 0 0 0 0 0
Row 2: 0 0 0 0 0 0
Row 3: 0 0 0 0 0 0
Row 4: 0 0 0 0 0 0

You add all of them together 6+6+6+6=24
Or you could do 6x4 and your answer would be 24
So the answer to the question is 24 seashells.

3 0

2 years ago

AC = Round your answer to the nearest hundredth.

dusya [7]

Answer:

AC ≈ 5.03

Step-by-step explanation:

We can solve the problem above using the trigonometric ratio, they are;

SOH CAH TOA

sin Ф = opposite / hypotenuse

cosФ= adjacent/ hypotenuse

tan Ф = opposite / adjacent

From the diagram above, in reference to angle B;

opposite =AC and adjacent =BC

Since we have opposite and adjacent, the best formula to use is

tanФ = opposite / adjacent

tan B = AC / BC

tan 40 = AC/ 6

Multiply both-side of the equation by 6

6× tan 40 = AC/ 6 × 6

At the right-hand side of the equation, 6 will cancel-out 6 leaving us with just AC

6×tan 40 = AC

5.034598 = AC

AC ≈ 5.03 to the nearest hundredths

4 0

3 years ago

80 3. # 765 = 945 Arrow way

Darina [25.2K]

What do you mean? I’m not sure

6 0

2 years ago

Read 2 more answers

James works for a delivery company. He gets paid a flat rate of $5 each day he works, plus an additional amount of money for eve

otez555 [7]

Answer:

(a) The rate of change for the money earned, measured as dollars per delivery, between 0 and 2 deliveries is $2.

(b) The rate of change is the same between the two time intervals.

Step-by-step explanation:

The rate of change for a variables based on another variable is known as the slope.

The formula to compute the slope is:

$\text{Slope}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

(a)

Compute the rate of change for the money earned, measured as dollars per delivery, between 0 and 2 deliveries as follows:

For, x₁ = 0 and x₂ = 2 deliveries the money earned are y₁ = $5 and y₂ = $9.

The rate of change for the money earned is:

$\text{Slope}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$=\frac{9-5}{2-0}\\\\=\frac{4}{2}\\\\=2$

Thus, the rate of change for the money earned, measured as dollars per delivery, between 0 and 2 deliveries is $2.

(b)

Compute the rate of change for the money earned, measured as dollars per delivery, between 2 and 4 deliveries as follows:

For, x₁ = 2 and x₂ = 4 deliveries the money earned are y₁ = $9 and y₂ = $13.

The rate of change for the money earned is:

$\text{Slope}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$=\frac{13-9}{4-2}\\\\=\frac{4}{2}\\\\=2$

The rate of change for the money earned, measured as dollars per delivery, between 2 and 4 deliveries is $2.

Compute the rate of change for the money earned, measured as dollars per delivery, between 6 and 8 deliveries as follows:

For, x₁ = 6 and x₂ = 8 deliveries the money earned are y₁ = $17 and y₂ = $21.

The rate of change for the money earned is:

$\text{Slope}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$=\frac{17-21}{8-6}\\\\=\frac{4}{2}\\\\=2$

The rate of change for the money earned, measured as dollars per delivery, between 6 and 8 deliveries is $2.

Thus, the rate of change is the same between the two time intervals.

8 0

2 years ago