Answer:
m∠C = 26°
m∠D = 108°
m∠E = 46°
Step-by-step explanation:
Set up the equation adding the expressions together to equal 180 (sum of all angles in a triangle)
(2x) + (x+3) + (5x-7) = 180
Remove the parentheses
2x + x+ 3 + 5x - 7 = 180
Add like terms
8x - 3 -7 = 8x -4 = 180
8x - 4 = 180
Add 4 on each side to cancel it out on the right
8x - 4 = 180
+4 = +4
8x = 184
Divide each side by 8 to get the variable by itself
8/8 =1 184/8 = 23
x = 23
Substitute x in eac expression
2x = 2(23) = 46°
x + 3 = 23 + 3 = 26°
5x - 7 = 5(23) - 7 = 115 -7 = 108
Chek it by adding all the degrees to make sure it equals 180
46 + 26 + 108 = 72 + 108 = 180
Using that 1 mile = 1,6 km so 5 miles = 5*1,6 = 8 km
and 250 miles = 250*1,6 = 400 km
Answer:
Hyperbola
Step-by-step explanation:
The polar equation of a conic section with directrix ± d has the standard form:
r=ed/(1 ± ecosθ)
where e = the eccentricity.
The eccentricity determines the type of conic section:
e = 0 ⇒ circle
0 < e < 1 ⇒ ellipse
e = 1 ⇒ parabola
e > 1 ⇒ hyperbola
Step 1. <em>Convert the equation to standard form
</em>
r = 4/(2 – 4 cosθ)
Divide numerator and denominator by 2
r = 2/(1 - 2cosθ)
Step 2. <em>Identify the conic
</em>
e = 2, so the conic is a hyperbola.
The polar plot of the function (below) confirms that the conic is a hyperbola.
Answer:
(a)
or 
(b)
or
Step-by-step explanation:
Given
--- North Dakota
--- Cheyenne, Wyoming
Solving (a): Inequality to compare both temperatures
From the given temperatures, we can conclude that:
or 
Because
i.e. 1 is greater than -2
or
i.e. -2 is less than 1
Solving (b): Inequality to compare the absolute values of the temperatures
We have:


The absolute values are:




By comparison:
or 
Because
i.e. 2 is greater than 1
or
i.e. 1 is less than 2
Division is the inverse of multiplication; therefore it depends on knowing the multiplication table.
The problem of division is to find what number times the Divisor will equal the Dividend. That number is called the Quotient. (Lesson 11.) To find the quotient, there is a method called short division.