All categories

2 years ago

-8x - 11x I really need help

Mathematics

1 answer:

Tema [17]2 years ago

4 0

Answer: -19x

Step-by-step explanation: In this problem, we're asked to simplify the expression.

The two parts of this expression, -8x and 11x are called terms. The numbers in front of the variables are called coefficients.

Because the variables, x and x are identical, the terms get a special name and they're called like terms.

To subtract like terms, we simply subtract their coefficients and add the variable on to the difference of the two numbers.

Since -8 (-11) is -19, -8x - 11x simplifies to -19x.

You might be interested in

Jill Hartman earns $750 per week, plus 3% of sales in excess of $6500. if Jill sells $25000 in the first week her earnings are ?

Nezavi [6.7K]

The answer is going to be: answer B.

Hope this helps =D

7 0

3 years ago

Read 2 more answers

1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat

brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

$x = -1$ is local maximum, $x = 1$ is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

$x = 1$ is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

$x = 0$ is local maximum, $x = 8$ is local minimum

4) increasing on [2,∞), decreasing on (-∞,2]

$x = 2$ is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

$x = 0$ is local minimum, $x = 4/9$ is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) $f(x) = 6x + 6/x$

$f\prime(x) = 6 - 6/x^2 = 0$ and $x \neq 0$

So, the roots are $x = -1$ and $x = 1$

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

$x = -1$ is local maximum, $x = 1$ is local minimum.

2) $f(x)=6-4/x+2/x^2$

$f\prime(x)=4/x^2-4/x^3=0$ and $x \neq 0$

So the root is $x = 1$

The function is increasing on the interval [1,∞)

The function is decreasing on the interval (-∞,0) ∪ (0,1]

$x = 1$ is absolute minimum.

3) $f(x) = 8x^2/(x-4)$

$f\prime(x) = (8x^2-64x)/(x-4)^2=0$ and $x \neq 4$

So the roots are $x = 0$ and $x = 8$

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

$x = 0$ is local maximum, $x = 8$ is local minimum.

4) $f(x)=6(x-2)^{2/3} +4=0$

$f\prime(x) = 4/(x-2)^{1/3}$ has no solution and $x = 2$ is crtitical point.

The function is increasing on the interval [2,∞)

The function is decreasing on the interval (-∞,2]

$x = 2$ is absolute minimum.

5) $f(x)=8\sqrt x - 6x$ for $x>0$

$f\prime(x) = (4/\sqrt x)-6 = 0$

So the root is $x = 4/9$

The function is increasing on the interval (0,4/9]

The function is decreasing on the interval [4/9,∞)

$x = 0$ is local minimum, $x = 4/9$ is absolute maximum.

5 0

2 years ago

Ron used 121 congruent equilateral triangles with 2 cm side lengths to form one large equilateral triangle. What is the perimete

Pepsi [2]

The number of smaller triangles along one side of the larger triangle is the square root of the total number of triangles. The perimeter of the large triangle is ...
3*(2 cm)*√121 = 66 cm

5 0

3 years ago

What is the slope of the line that passes through the points (9, 4)(9,4) and (3, 9)(3,9)? Write your answer in simplest form.

nalin [4]

Answer:

I’m guessing the double points is a typo.

Slope: -5/6

Step-by-step explanation:

Hope this helps <3

Btw love your username <333

6 0

2 years ago

Read 2 more answers

Choose the equation of the horizontal line that passes through the point (2, 3).

Marizza181 [45]

The equation for the horizontal line is
y=3

5 0

2 years ago