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3 years ago

If you can help,please answer :)

Mathematics

1 answer:

Katarina [22]3 years ago

6 0

Answer:

2-4=-2->subtraction

2+-4=-2->addition

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Verify the identity algebraically:<br> Csc(-x)tanx =-secx

weqwewe [10]

Step-by-step explanation:

Recall that

$\sin(-x) = -\sin x$

Therefore,

$\csc(-x) = \dfrac{1}{\sin(-x)} = -\dfrac{1}{\sin x}$

$\csc(-x)\tan x = \left(-\dfrac{1}{\sin x}\right)\left(\dfrac{\sin x}{\cos x}\right)$

$\:\:\:\:\:\:\:\:\:= -\dfrac{1}{\cos x} = -\sec x$

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2 years ago

Rewrite the following polynomial in standard form.<br> -x^2-10+x^3

ELEN [110]

Answer:

Step-by-step explanation:

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2 years ago

Remy has $14,000 to invest in two mutual funds. One fund pays interest at 4% per year and the other fund pays interest at 7% per

AnnyKZ [126]

$4,200 at 4%, $9,800 at 7%

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2 years ago

5/6w+21=-1/3(2w-9).

oksian1 [2.3K]

I believe this question logically tells us to find the value of w. The two equations are already equated. Since there is 1 unknown and 1 equation, the system is solvable. The solution is as follows:

5/(6w+21) = -1/3(2w - 9)
5/(6w+21) = -1/(6w - 27)
Cross multiplying the terms:
5(6w - 27) = -1(6w +21)
30w - 135 = -6w - 21
30w + 6w = -21 + 135 = 114
36w = 114
w = 114/36
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7 0

3 years ago

KLMN is a parallelogram,

Aleonysh [2.5K]

Answer:

Ok soo.

Step-by-step explanation:

sum of two adjacent angles of parallelogram is 180

so angle K + angle L = 180

as AK bisects angle K and LA bisects angle L

so, angle AKL + angle ALK = 180 /2 = 90

in triangle AKL,

angle AKL + angle ALK+angle KAL = 180(sum of all angles in triangle = 180)

so, from above two equations,

angle KAL = 90

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4 0

2 years ago

If you can help,please answer :)​

If you can help,please answer :)