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ivanzaharov [21]
3 years ago
15

Rayshad has $238.12 deducted from his monthly annual pay for group insurance. His employer pays 85% of the cost. What is the ann

ual premium?
Mathematics
1 answer:
umka21 [38]3 years ago
5 0
202.402
Explanation
282.12 x .85
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Guys help needed fast pls​
Kaylis [27]

Answer:

\frac{61}{8}

Step-by-step explanation:

If a polynomial p(x) is divided by a factor (x + h ) then the remainder is

f(- h)

Here p(x)is divided by (x - \frac{1}{2} ) thus evaluate p(\frac{1}{2} ) for remainder

p(\frac{1}{2} )

= (\frac{1}{2} )³ - 2(\frac{1}{2} )² + 8

= \frac{1}{8} - \frac{1}{2} + 8

= \frac{61}{8}

8 0
3 years ago
If 20 is 20% of 20% of an integer what is that integer?
Harman [31]
N(20/100)(20/100)=20

n(1/5)(1/5)=20

n/25=20

n=500
7 0
3 years ago
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PSYCHO15rus [73]

Answer:

There is a 95% chance that values will be within ±2 standard deviations of the mean.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this question:

According to the empirical rule, 95% of the measures are within 2 standard deviations of the mean. So the correct statement is:

There is a 95% chance that values will be within ±2 standard deviations of the mean.

4 0
3 years ago
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Leno4ka [110]

Answer:

it is c for shore i got it right

4 0
2 years ago
Yellowstone National Park has 124 wolves living in it. The park covers 3472 square miles. What is the population density of wolv
Serggg [28]
<span>The answer is 0.0357 Wolves/mi. The total amount of square miles at the park is 3472, with 124 wolves living in the park. So we take the miles of the park and divide it by the number of wolves living in the park. 124/3472=0.0357 wolves/mil</span>
3 0
3 years ago
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