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3 years ago

7

Write an equation that finds m, given E and c

2 answers:

kogti [31]3 years ago

5 0

Answer:

A

Step-by-step explanation:

given E = mc² or

mc² = E ( isolate m by dividing both sides by c² )

m = $\frac{E}{c^{2} }$ → A

gregori [183]3 years ago

3 0

Step-by-step explanation:

given E = mc² or

mc² = E ( isolate m by dividing both sides by c² )

m = \frac{E}{c^{2} }
c
2

E

→ A

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Jane will draw one card from the regular deck of 52 cards. In how many ways can she choose a jack or a black card?

elena-s [515]

Answer:

28

Step-by-step explanation:

In a regular 52 card deck, 26 are black (clubs or spades). Additionally, there are two red jacks (diamonds and hearts). This equals 28/52. As a probability, it would be 28/52=14/26=7/13. This could also be expressed as a percentage or decimal. 0.538 or 53.8%. But the question asks <em>how many ways</em> can she choose a jack or black card, so I’m assuming they don’t want the probability, just the number, which is 28.

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3 years ago

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3 years ago

What is the equation of the line that is perpendicular to y = -2/3x + 4 and that passes through (–2,–2)?

Rama09 [41]

Answer: y = 3/2x + 1

Step-by-step explanation: For a perpendicular line, take the reciprocal of "m" and reverse the sign.

- 2/3 becomes +3/2

Then substitute the y and x values of the given coordinate into the equation and solve for "b"

y = mx + b

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-2 = -3 + b

-2 +3 = b

+1 = b Substitute for b in y = (3/2)x + 1

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3 years ago

A new health drink has 130% of the recommended daily allowance (RDA) for a certain vitamin . The rad for this vitamin is 45 mg.

Maslowich

Answer:

58.5 mg

Step-by-step explanation:

Drink: 130% of RDA of vitamin X

RDA vitamin X = 45mg

130% of 45 = mg in the drink

130% = 130/100 = 1.3

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3 years ago

A manager at a local company asked his employees how many times they had given blood in the last year. The results of the survey

Lubov Fominskaja [6]

Answer:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

Step-by-step explanation:

For this case we have the following distribution given:

X 0 1 2 3 4 5 6

P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02

For this case we need to find first the expected value given by:

$E(X) = \sum_{i=1}^n X_i P(X_I)$

And replacing we got:

$E(X)= 0*0.3 +1*0.25 +2*0.2 +3*0.12 +4*0.07+ 5*0.04 +6*0.02=1.61$

Now we can find the second moment given by:

$E(X^2) =\sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97$

And the variance would be given by:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

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3 years ago