Answer:
191.316 K or -81.684 °C
Explanation:
From general gas law,
P₁V₁/T₁ = P₂V₂/T₂ ................ Equation 1
Where P₁ = Initial pressure, V₁ = Initial volume, T₁ = Initial temperature, P₂ = Final pressure, V₂ = Final volume, T₂ = Final Temperature.
Make T₂ the subject of the equation.
T₂ = P₂V₂T₁/P₁ V₁ ............... Equation 2
Given: P₁ = 5.00×10⁶ Pa, T₁ = 25.0°C = 298 K, P₂ = 1.07×10⁶.
Let: V₁ = y cm³, V₂ = 3y cm³
Substitute into equation 2,
T₂ = (1.07×10⁶×298×3y)/(5.00×10⁶×y)
T₂ =191.316 K.
Hence the final temperature = 191.316 K or -81.684 °C
