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Flauer [41]
2 years ago
8

When a certain gas under a pressure of 5.00 × 106 Pa at 25.0°C is allowed to expand to 3.00 times its original volume, its final

pressure is 1.07 × 106 Pa. What is its final temperature?
Physics
1 answer:
12345 [234]2 years ago
4 0

Answer:

191.316 K or -81.684 °C

Explanation:

From general gas law,

P₁V₁/T₁ = P₂V₂/T₂ ................ Equation 1

Where P₁ = Initial pressure, V₁ = Initial volume, T₁ = Initial temperature, P₂ = Final pressure, V₂ = Final volume, T₂ = Final Temperature.

Make T₂ the subject of the equation.

T₂ = P₂V₂T₁/P₁ V₁ ............... Equation 2

Given: P₁ = 5.00×10⁶ Pa, T₁ = 25.0°C = 298 K, P₂ = 1.07×10⁶.

Let: V₁ = y cm³, V₂ = 3y cm³

Substitute into equation 2,

T₂ = (1.07×10⁶×298×3y)/(5.00×10⁶×y)

T₂ =191.316 K.

Hence the final temperature = 191.316 K or -81.684 °C

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Answer:

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Two tennis balls have the same mass m and are served at speeds v1=30 m/s and v2=60 m/s.

The kinetic energy of the first ball is:

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\displaystyle K_2=\frac{1}{2}m\cdot 60^2

\displaystyle K_2=\frac{1}{2}m\cdot 3600

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Being m the same for both balls, the second ball has more kinetic energy than the first ball.

To find out how much, we find the ratio:

\displaystyle \frac{K_2}{K_1}=\frac{1800m}{450m}

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\displaystyle \frac{K_2}{K_1}=4

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Complete question:

Point charges q1=- 4.10nC and q2=+ 4.10nC are separated by a distance of 3.60mm , forming an electric dipole. The charges are in a uniform electric field whose direction makes an angle 36.8 ∘ with the line connecting the charges. What is the magnitude of this field if the torque exerted on the dipole has magnitude 7.30×10−9 N⋅m ? Express your answer in newtons per coulomb to three significant figures.

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Explanation:

Given;

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