Answer:
kinetic energy of the train = 2,910.6 x 10⁷ joule
Explanation:
Given:
Mass of train = 3.3 x 10⁷ kg
Speed of train = 42 m/s
Find:
kinetic energy of the train
Computation:
kinetic energy = (1/2)(m)(v²)
kinetic energy of the train = (1/2)(3.3 x 10⁷)(42²)
kinetic energy of the train = (1/2)(3.3 x 10⁷)(1,764)
kinetic energy of the train = (3.3 x 10⁷)(882)
kinetic energy of the train = 2,910.6 x 10⁷ joule
If we have I= 7.5 A:
I think my solution might just help you answer the problem on your own:
You have the formulas correct, watch your signs and BRACKETS.
B = μ0/(2π) (Current) / (Perpendicular distance)
Since μ0=4π E -7 Tm/A, we have:
B1 = (4πE-7 Tm/A)(7.5 A)/[2π (0.030 m)] = 5E-5 T
B2 = (4πE-7 Tm/A)(-7.5 A)/[2π (0.150 m)] = -1E-1 T
So BA = B1 + B2 = ?
(It looks like you just left out the square brackets, hence multiplying Pi and 0.03 and 0.15 instead of dividing them.)
<span>For the point B, the two distances are -0.060 m and +0.060 m. Be careful with the signs. Unlike point A, the two components will have the same sign.</span>
The prokaryotic cells are indeed smaller than the eularyotic cells.
Eukaruotic cell size -10-100um
Prokaryotic cell size - 1-10 um
the answer is.................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................<u>FALSE.</u> You are welcome everybody :) GOod luck to all of you people. Peace love and coconut oil ॐ
Answer:
The tension on the clotheslines is 
Explanation:
The diagram illustrating this question is shown on the first uploaded image
From the question we are told that
The distance between the two poles is 
The mass tie to the middle of the clotheslines 
The length at which the clotheslines sags is 
Generally the weight due to gravity at the middle of the clotheslines is mathematically represented as
let the angle which the tension on the clotheslines makes with the horizontal be 
which mathematically evaluated using the SOHCAHTOA as follows
=> ![\theta = tan^{-1}[\frac{4}{6} ]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%20tan%5E%7B-1%7D%5B%5Cfrac%7B4%7D%7B6%7D%20%5D)
=> 
So the vertical component of this tension is mathematically represented a
Now at equilibrium the net horizontal force is zero which implies that
=> 
substituting values
substituting values
