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8_murik_8 [283]
4 years ago
9

Factor completely 3x2 + 9x – 54. ...?

Mathematics
1 answer:
anyanavicka [17]4 years ago
8 0
3x² + 9x - 54 :(3)
x² + 3x - 18
(x-3)*(x+6)
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Which value is equivalent to 7 multiplied by 3 multiplied by 2 whole over 7 multiplied by 5, the whole raised to the power of 2
vivado [14]

Answer:

Option b) 36 over 25 is correct

That is given expression is equivalent to \frac{36}{25}

Step-by-step explanation:

Given expression can be written as below:

(\frac{7\times 3\times 2}{7\times 5})^2\times \frac{7^0}{5^{-3}}\times 5^{-9}

To find the value of given expression:

(\frac{7\times 3\times 2}{7\times 5})^2\times \frac{7^0}{5^{-3}}\times 5^{-9}=(\frac{6}{5})^2\times (\frac{1}{5^{-3}})^3\times \frac{1}{5^9}

=(\frac{6}{5})^2\times (5^3)^3\times \frac{1}{5^9}

=\frac{36}{25}\times 5^9\times \frac{1}{5^9}

=\frac{36}{25}

Therefore (\frac{7\times 3\times 2}{7\times 5})^2\times \frac{7^0}{5^{-3}}\times 5^{-9}=\frac{36}{25}

Option b) 36 over 25 is correct

That is given expression is equivalent to \frac{36}{25}

4 0
4 years ago
Please help! I feel like I'm drowning :(
algol13

Answer:

1d = -3

2b = 2

2c = 1

3a = 3

3d = 4

Step-by-step explanation:

Polynomial 1: x^2-8x+15

Multiply the leading coefficient, 1, and the last term, 15. You get: 15.

Then, list out the factors of 15 and the addends of -8 until you get two of numbers that are the same:

Factors of 15: -5 * -3

Addends of -8: -5 + -3

Replace the -8x with -5x - 3x:

x^2-5x-3x+15

Put parentheses around the first 2 terms & last 2 terms and factor like so:

(x^2-5x)-(3x+15)

x(x-5)-3(x-5)

(x-5)(x-3)

Looking at the answer (ax + b)(cx + d), d would correspond with -3.

Polynomial 2: 2x^3-8x^2-24x

First factor out the x:

x(2x^{2}-8x-24)

Divide the polynomial inside by 2 and place the 2 outside with the x:

2x(x^2-4x-12)

Then find the factors of 1*-12 and the addends of -4 and see which two numbers match:

Factors of -12: -6 * 2

Addends of -4: -6 + 2

Replace the -8x with -6x + 2x:

2x(x^2-6x+2x-12)

Put parentheses around the first 2 terms & last 2 terms and factor like so:

2x((x^2-6x)+(2x-12))

2x(x(x-6)+2(x-6))

2x((x+2)(x-6))

2x(x+2)(x-6)

Looking at the answer (2x)(ax + b)(cx + d), b & c would correspond with 2 & 1.

Polynomial 3: 6x^2+14x+4

Divide the polynomial by 2:

(2)(3x^2+7x+2)

Find the factors of 3*2 and the addends of 7 and see which two numbers match:

Factors of 6: 6 * 1

Addends of 7: 6 + 1

Replace the 7x with 6x + x:

(2)(3x^2+6x+x+2)

Put parentheses around the first 2 terms & last 2 terms and factor like so:

(2)((3x^2+6x)+(x+2))

(2)(3x(x+2)+(x+2))

(2)((3x+1)(x+2))

(2)(3x+1)(x+2)

Then multiply the 2 with the (x+2) and here's your final answer:

(3x+1)(2x+4))

Looking at the answer (ax + b)(cx + d), a & d correspond with 3 & 4.

Hope that helps (●'◡'●)

(This took a while to write, sorry about that)

8 0
3 years ago
If s²=19, what is the value of (s+1)(s-1)
julia-pushkina [17]
(s + 1)(s - 1) = s^2 - 1
= 19-1 = 18
6 0
4 years ago
What is the solution to the inequality -8x + 4 < -4?
never [62]

Answer:

x > 1

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

-8x + 4 < -4

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Subtract 4 on both sides:                    -8x < -8
  2. Divide -8 on both sides:                       x > 1

Here we see that any value <em>x</em> greater than 1 would work as a solution.

6 0
3 years ago
Given the function: f(x) = x2 – 2x How can you restrict the domain so that f(x) has an inverse? What is the equation of the inve
VMariaS [17]

Answer:

B. x ≥ 1; f Superscript negative 1 Baseline (x) = 1 + StartRoot x + 1 EndRoot

Step-by-step explanation:

Dude answered his own question

6 0
3 years ago
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