4b²+20b+25=0
Divide everything by 4
b²+5b+ 6.25=0
use the quadratic formula
x= (-b+ or - √b²-4ac) /2a
x= (-5 + or - √5²-4*1*6.25) /2(1)
x= -5/2 so
in this case, b= -5/2
Answer:
Its a straight line
Step-by-step explanation:
Answer:
The length of AA' = √29 = 5.39
Step-by-step explanation:
* Lets revise how to find the length of a line joining between
any two points in the coordinates system
- If point A is (x1 , y1) and point B is (x2 , y2)
- The length of AB segment √[(x2 - x1)² + (y2 - y1)²]
* Lets use this rule to solve the problem
∵ Point A is (0 , 0)
∵ Point A' = (5 , 2)
∵ (x2 - x1)² = (5 - 0)² = 5² = 25
∵ (y2 - y1)² = (2 - 0)² = 2² = 4
∴ The length of AA' = √(25 + 4) = √29 = 5.39
The x would equal 0 and the y would equal 3
Answer: $113.55
Step-by-step explanation:
add up the cost of the lesson, boots, board, and ticket
the lesson costs $33.80 and the ticket costs $25, these cover the whole day so no need to be multiplied. the boots cost $2 and the board costs $8.95 each hour, jim will need to pay the cost of both 5 times for 5 hours.
here is the equation to solve
33.80 + 5(8.95 + 2.00) + 25 =
33.80 + 5(10.95) + 25 =
33.80 + 54.75 + 25 =
33.80 + 79.75 = 113.55
the total cost is $113.55
